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Irina18 [472]
3 years ago
13

Aranyasarkar stopppp

Chemistry
1 answer:
tino4ka555 [31]3 years ago
5 0
Hence solve it to get the answer

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The ability of a substance to be hammered or rolled into thin sheets is called ________
zaharov [31]

Answer: Malleability

Explanation: is a physical property of metals that defines their ability to be hammered, pressed, or rolled into thin sheets without breaking. In other words, it is the property of a metal to deform under compression and take on a new shape.

3 0
3 years ago
O2- is the Lewis ______ in the following reaction
matrenka [14]

O^{2-} is the Lewis base in the following reaction:

SO_3(g) + O^{2-}(aq)   →  SO_4^{2-}(aq)

<h3>What is lewis base? </h3>

Lewis base is a species that donates an electron pair.

In the above-given chemical equation, the O^{2-}is the lewis base which is donating an electron pair to the central atom of SO_3 to form SO_4^{-2}.

Hence, O^{2-} is the Lewis base in the following reaction:

SO_3(g) + O^{2-}(aq)   →  SO_4^{2-}(aq)

Learn more about the lewis base here:

brainly.com/question/15570523

#SPJ1

3 0
2 years ago
Given the balanced equation, 2 H2 + O2 -&gt; 2 H2O, answer the following
9966 [12]

Answer: O_2 is the limiting reagent

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} H_2=\frac{10.0g}{2g/mol}=5.00moles

\text{Moles of} O_2=\frac{20.0g}{32g/mol}=0.625moles

The balanced chemical reaction is :

2H_2+O_2\rightarrow 2H_2O

According to stoichiometry :

1 moles of O_2 require = 2 moles of H_2

Thus 0.625 moles of O_2 will require=\frac{2}{1}\times 0.625=1.25moles of H_2

Thus O_2 is the limiting reagent as it limits the formation of product and H_2 is the excess reagent as it is present more than the required amount.

8 0
3 years ago
Arrange the following atoms in order of increasing first ionization energy: He, Be, Se, Ne
Alex17521 [72]

Answer:

Be (899 kj/mol) , Se (940.9 kj/mol), Ne(2081 kj/mol), He (2370 kj/mol),

Explanation:

For noble gases as they have complete octet so they require high amount of energy to remove the electron.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

8 0
3 years ago
How does the density of aluminum compare with the density of gold
rewona [7]
Gold has a very high density of about 19.32g/cm^3 while Aluminum has a low density of 2.7 gm/cm^3 which means gold can pack more amount of matter in a comparatively small space as compared to Aluminum.
3 0
3 years ago
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