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Mama L [17]
3 years ago
8

How is this reaction classified?

Chemistry
1 answer:
boyakko [2]3 years ago
3 0
B is the answer

hope this helps
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Ammonium phosphate NH43PO4 is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric a
ira [324]

Answer:

0.767 moles of ammonium phosphate are produced

Explanation:

The reaction of ammona (NH3), with phosphoric acid is:

3 NH3 + H3PO4 → (NH4)3PO4

<em>Where 3 moles of ammonia reacts per mole of H3PO4 to produce 1 mole of ammonium phosphate.</em>

<em />

If 2.3 moles of ammonia reacts, the moles of ammonium phosphate produced if phosphoric acid is in excess are:

2.3 moles NH3 * (1 mole (NH4)3PO4 / 3 moles NH3) =

<h3>0.767 moles of ammonium phosphate are produced</h3>

<em />

5 0
3 years ago
Which of the following is TRUE about when two atoms form a bond? a. Repulsion is greater than attraction b. Neither atoms will h
mixer [17]

Answer:

b:   Neither atoms will have a full valence shell

Explanation:

I think sooo

8 0
3 years ago
Label each molecule with the name of its shape. click on the 3d models to rotate the molecules.
SIZIF [17.4K]
??? There's no image?..
6 0
4 years ago
Balance the following chemical equation (if necessary):
dybincka [34]

Answer: SiCl₄(s) + 4 H₂O(l) → H₄SiO₄(aq) + 4 HCl(aq)

Explanation:
You can pretend there is an imaginary line splitting the chemical equation into two on the arrow to help balance the equation.
Balance out chlorine on both sides, add the coefficient 4 to HCl
now there are 4 chlorines on the left and the right side.
Then, balance out Hydrogen on both sides, add the coefficient 4 to H₂O
now, there are 4*2=8 hydrogens on the left and 4+4=8 hydrogens on the right.
Counting the total number of atoms on both sides of the arrow, the equation is balanced
1 Si = 1 Si
4 Cl = 4 Cl
4 O = 4 O
8 H = 8 H

3 0
2 years ago
Read 2 more answers
The average molecular weight for element X is 59.97 g/mol. There are two known isotopes of element X, one weighing 59 g/mol, and
Temka [501]

Answer:

The correct answer is:48.5% X-59, 51.5% X-61

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i.....(1)

Let the fractional abundance of X-59 isotope be 'x'. So, fractional abundance of X-61 isotope will be '1 - x'

For X-59 isotope:

Mass of  X-59 isotope =59 g/mol

Fractional abundance of X-59 isotope = x

For  X-61 isotope:

Mass of  X-61 isotope = 61 g/mol

Fractional abundance of  X-61 isotope = 1 - x

Average atomic mass of chlorine = 35.4527 amu

Putting values in equation 1, we get:

59.97 g/mol=[(59 g/mol\times x)+(61 g/mol\times (1-x))]\\\\x=0.515

Percentage abundance of X-59 isotope = 0.515\times 100=51.5\%

Percentage abundance of X-61 isotope = (1-0.515)=0.485\times 100=48.5\%

Hence, the percentage abundance of both the isotopes X-59and X-61 are 51.5% and 48.5% respectively.

4 0
3 years ago
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