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igomit [66]
3 years ago
8

How much heat is required to raise the temperature of 10.35g of CCl4 from 32.1°c to 56.4°c

Chemistry
1 answer:
Travka [436]3 years ago
4 0
We are going to use this formula:

Q = M*C*ΔT

when Q is the heat required 

M is the mass of CCl4 = 10.35 g

C is the specific heat capacity of CCl4 = 0.874J/g.c

and ΔT the change in temperature = 56.4 - 32.1 °C =24.3 °C

∴ Q = 10.35g * 0.874 * 24.3 °C

       = 219.8 J
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Answer:

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Explanation:

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Are usually solid shiny and conductive object
crimeas [40]
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4 years ago
Calculate the fraction of atoms in a sample of argon gas at 400 K that have an energy of 12.5 kJ or greater. Report your answer
emmainna [20.7K]

Answer:

0.023

Explanation:

The Arrhenius' equation states that:

k = A*e^{\frac{-Ea}{RT}

Where k is the velocity constant of the reaction, A is the constant of the collisions, Ea is the activation energy (the energy necessary to the molecules have so the reaction will happen), R is the gas constant (8.314 J/molK) and T is the temperature.

This equation is derivated of:

k = pZf

Where

p=fraction of collisions that occur with reactant molecules properly oriented

f=fraction of collisions having energy greater than the activation energy

Z=frequency of collisions

Thus, p*Z = A, and

f = e^{\frac{-Ea}{RT} }

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f = e^{\frac{-12500}{8.314*400} }

f = 0.023

6 0
3 years ago
If 4.88 grams of zn react with 5.03 grams of s8 to produce 6.02 grams of zns, what are the theoretical yield and percent yield o
nataly862011 [7]
<span>Balance the equation
    8Zn + S8 -----> 8ZnS
    work out how much ZnS is possible if all of each reagent were to react. The reagent that produces the least product is the limiting reagent.
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  8 moles Zn reacts to form 8 moles ZnS
  Therefore moles ZnS possible = moles Zn = 0.07464 moles

    moles S8 = 5.03 g / 256.48 g/mol = 0.01961 mol
  1 mole S8 reacts to form 8 moles ZnS
  Therefore moles ZnS possible = 8 x moles S8 = 0.1569 mol

    The amount of Zn provided gives the least ZnS, therefore Zn is the limiting reagent.
    The theoretical yield is the maximum possible yield possible from the reagents provided. It is the amount of product that will form if all the limiting reagent reacts.
  So in this case 4.88 g Zn yields 0.07464 mol ZnS

    theoretical mass ZnS = molar mass x moles
  = 97.44 g/mol x 0.07464 mol
  = 7.27 g

    % yield = actual yield / theoretical yield x 100/1
  = 6.02 g / 7.27 g x 100/1
  = 82.8 %</span>
8 0
3 years ago
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Answer:

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