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igomit [66]
3 years ago
8

How much heat is required to raise the temperature of 10.35g of CCl4 from 32.1°c to 56.4°c

Chemistry
1 answer:
Travka [436]3 years ago
4 0
We are going to use this formula:

Q = M*C*ΔT

when Q is the heat required 

M is the mass of CCl4 = 10.35 g

C is the specific heat capacity of CCl4 = 0.874J/g.c

and ΔT the change in temperature = 56.4 - 32.1 °C =24.3 °C

∴ Q = 10.35g * 0.874 * 24.3 °C

       = 219.8 J
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Answer:

0.6 moles NH₃

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Then we <u>convert H₂ moles (the limiting reactant) to NH₃ moles</u>, keeping in mind the <em>stoichiometry of the reaction</em>:

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eimsori [14]
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8 0
3 years ago
The mode of 12, 17, 16, 14, 13, 16, 11, 14,13, 16 is​
RUDIKE [14]

Answer:

<h2>Mean = 14.2</h2><h2>Median = 14</h2><h2>Mode = 16</h2><h2>Range = 6</h2>

Explanation:

__________________________________________________________

<em>Mean = 14.2 or 14</em>

<em>Median = 14</em>

<em>Mode = 16</em>

<em>Range = 6</em>

<em>__________________________________________________________</em>

<em>Here are all the numbers from least to greatest order: 11, 12, 13, 13, 14, 14, 16, 16, 16, 17.</em>

<em>__________________________________________________________</em>

<em>Hope this helps! <3</em>

<em>__________________________________________________________</em>

8 0
3 years ago
Help please !!!
castortr0y [4]

Answer:

B

pls mark

Explanation:

7 0
3 years ago
Read 2 more answers
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