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igomit [66]
4 years ago
8

How much heat is required to raise the temperature of 10.35g of CCl4 from 32.1°c to 56.4°c

Chemistry
1 answer:
Travka [436]4 years ago
4 0
We are going to use this formula:

Q = M*C*ΔT

when Q is the heat required 

M is the mass of CCl4 = 10.35 g

C is the specific heat capacity of CCl4 = 0.874J/g.c

and ΔT the change in temperature = 56.4 - 32.1 °C =24.3 °C

∴ Q = 10.35g * 0.874 * 24.3 °C

       = 219.8 J
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