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SVEN [57.7K]
3 years ago
12

In Mrs. Trach’s class, 18 students prefer to do their homework before dinner. In Ms. Love-Benson's class, 20 students prefer to

do their homework before dinner. Does that mean a higher percent of students in Ms. Love-Benson's class prefer to do their homework before dinner? HELP
Mathematics
2 answers:
deff fn [24]3 years ago
5 0
Yes because in Mrs. Benson‘s class there are 20 students and in Mrs Tracy’s class there are only 18
Annette [7]3 years ago
4 0

Answer:

The given information is not sufficient to make any conclusion.

We need total number of students in each class to determine the percentage of students in each class who prefer to do their homework before dinner.

If the total number is same in each class, then we can say yes otherwise we need exact numbers.

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Evaluate the Expression B^2-4 ac given by that a = -2 ,, b= -2 and c =2​
Lapatulllka [165]

F* you B*!!!!!! Your so S*! That's the easiest thing in the world!!

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3 years ago
The home run percentage is the number of home runs per 100 times at bat. A random sample of 43 professional baseball players gav
Andru [333]

Step-by-step explanation:

(a) Yes, if you enter all 43 values into your calculator, you calculator should report:

xbar = 2.293

s = 1.401

(b)

Note: Most professors say that is sigma = the population standard deviation is unknown (as it is unknown here), you should construct a t-confidence interval.

xbar +/- t * s / sqrt(n)

2.293 - 1.684 * 1.401 / sqrt(43) = 1.933

2.293 - 1.684 * 1.401 / sqrt(43) = 2.653

Answer: (1.933, 2.653)

Note: To find the t-value that allows us to be 90% confident, go across from df = 43-1 = 42 (round down to 40 to be conservative since 42 in not in the table) and down from (1-.90)/2 = .05 or up from 90% depending on your t-table. So, the t-critical value is 1.684.

Note: If you can use the TI-83/84, it will construct the following CI using df = 42 (ie t = 1.681).

2.293 +/- 1.681 * 1.401 / sqrt(43)

(1.934, 2.652)

Note: Some professors want you to construct a z-CI when the sample size is large. If your professor says this, the correct 90% CI is:

2.293 +/- 1.645 * 1.401 / sqrt(43)

(1.942, 2.644)

Note: To find the z-value that allows us to be 90% confident, (1) using the z-table, look up (1-.90)/2 = .05 inside the z-table, or (2) using the t-table, go across from infinity df (= z-values) and down from .05 or up from 90% depending on your t-table. Either way, the z-critical value is 1.645.

(c)

Note: Again, most professors say that is sigma = the population standard deviation is unknown (as it is unknown here), you should construct a t-confidence interval.

xbar +/- t * s / sqrt(n)

2.293 - 2.704 * 1.401 / sqrt(43) = 1.715

2.293 - 2.704 * 1.401 / sqrt(43) = 2.871

Answer: (1.715, 2.871)

Note: To find the t-value that allows us to be 99% confident, go across from df = 43-1 = 42 (round down to 40 to be conservative since 42 in not in the table) and down from (1-.99)/2 = .005 or up from 99% depending on your t-table. So, the t-critical value is 2.704.

Note: If you can use the TI-83/84, it will construct the following CI using df = 42 (ie t = 2.698).

2.293 +/- 2.698 * 1.401 / sqrt(43)

(1.717, 2.869)

Note: Again, some professors want you to construct a z-CI when the sample size is large. If your professor says this, the correct 99% CI is:

2.293 +/- 2.576 * 1.401 / sqrt(43)

(1.742, 2.843)

Note: To find the z-value that allows us to be 99% confident, (1) using the z-table, look up (1-.99)/2 = .005 inside the z-table, or (2) using the t-table, go across from infinity df (= z-values) and down from .005 or up from 99% depending on your t-table. Either way, the z-critical value is 2.576.

(d)

Tim Huelett 2.5

Since 2.5 falls between (1.715, 2.871), we see that Tim Huelett falls in the 99% CI range. So, his home run percentage is NOT significantly different than the population average.

Herb Hunter 2.0

Since 2.0 falls between (1.715, 2.871), we see that Herb Hunter falls in the 99% CI range. So, his home run percentage is NOT significantly different than the population average.

Jackie Jensen 3.8.

Since 3.8 falls above (1.715, 2.871), we see that Jackie Jensen falls in the 99% CI range. So, his home run percentage IS significantly GREATER than the population average.

(e)

Because of the Central Limit Theorem (CLT), since our sample size is large, we do NOT have to make the normality assumption since the CLT tells us that the sampling distribution of xbar will be approximatley normal even if the underlying population distribution is not.

6 0
3 years ago
Find Distance (4,6) (-4,-3)​
vampirchik [111]

Answer:

\sqrt{145}

Step-by-step explanation:

The distance formula states that the distance between two points (a,b) and (c,d) is \sqrt{(a-c)^2+(b-d)^2}.

The two points we have are (4,6) and (-4,-3). Plugging these numbers into the distance formula, we have

\sqrt{(4-(-4))^2+(6-(-3))^2.

Simplifying with order of operations, first using the distributive property, gives

\sqrt{(4+4)^2+(6+3)^2.

Squaring and adding gives

\sqrt{(4+4)^2+(6+3)^2}=\sqrt{8^2+9^2}\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~=\sqrt{64+81}\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~=\boxed{\sqrt{145}},

which is the answer in simplest form. This also rounds to about 12.04.

7 0
2 years ago
Simplify: 45÷3+2×8-12+30​
Phantasy [73]

Answer:

49

Step-by-step explanation:

3 0
3 years ago
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Order these weights from lightest to heaviest 10 ounces 1 pond and 1 ounce
Alchen [17]
1 ounce, 10 ounces, 1 pound.

1 pound = 16 ounces
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3 years ago
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