Equation :
[x(x+4)]/2=6 (as (b*h)/2=A)
x*x + 4*x -12 = 0
so, x = 2 units(as -6 is negative)
Answer:
∠ADB≅∠ABC by the Alternate Interior Angles Theorem
∠CAD≅∠ACB by the Alternate Interior Angles Theorem
∠BAD and ∠ADV are supplementary by the Consecutive Interior Angle Theorem
∠ABC and ∠BCD are supplementary by the Consecutive Interior Angle Theorem
<span>(((-3) + (-13)) / 2, ((-3) + (-13)) / 2) </span>
<span>= (-16 / 2, -16 / 2) </span>
<span>= (-8, -8)
1 = D</span>
Answer:
x = -0.2 and x = -3.5
Step-by-step explanation:
Combine like terms in the given equation, by subtracting 2x^2 from both sides:
6x^2 + 15x + 3 = 2x^2
-2x^2 = -2x^2
----------------------------------
4x^2 + 15x + 3 = 0
This is a quadratic equation. We'll find the two solutions using the quadratic equation
-b ± √(b^2 - 4ac)
x = ---------------------------
2a
Here the coefficients of the quadratic are a = 4, b = 15 and c = 3.
Thus, the discriminant b^2 - 4ac is 15^2 - 4(4)(3), or +177
and from that we know we'll find two real, unequal roots.
-15 ± √177
The roots are: x = ------------------- , or x = -0.2 and x = -3.5
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