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3 years ago

If you help me I'll make as brilliant

Mathematics

1 answer:

Damm [24]3 years ago

3 0

Answer:

Think it’s A

Step-by-step explanation:

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Through: (-2, -1), slope = -1

oksano4ka [1.4K]

y= -1x -3

that's equation of the line

7 0

3 years ago

A rectangle has a perimeter of 26 units. The length of the rectangle is 2X+3 and the width is 3X. What is the width of the recta

densk [106]

Answer:

X = 2

Step-by-step explanation:

Divided 26 (total perimeter) by 4 = maximum side length possible = 26÷4 =.6.5

I used the trial and error technique

Guessed it was 2 working out to see if i was right or wrong:

Length: 2(2) + 3 = 4+3 = 7

Width: 3(2) = 6

7+7+6+6 = 26

Therefore X = 2

3 0

4 years ago

State 5.126 to two decimal places

Kryger [21]

Answer:

5.13

Step-by-step explanation:

Look at the number at the end, and if it's 5 or more, round up. the 6 is greater than or equal to 5, so you round up, dropping the six and making the 2 into a 3, giving you 5.13.

7 0

3 years ago

Ellie borrows money at a year simple rate of 6 1/2% after 4 years ellie owes 39 interest

kupik [55]

Answer: Ellie borrowed $150.

Step-by-step explanation:

I = PRT

39 = P x 0.065 x 4

39 = P x 0.26

Divide both sides by 0.26

150 = P

6 0

3 years ago

25% of American households have only dogs (one or more dogs) 15% of American households have only cats (one or more cats) 10% of

sergeinik [125]

Answer:

a) P=0.2503

b) P=0.2759

c) P=0.3874

d) P=0.2051

Step-by-step explanation:

We have this information:

25% of American households have only dogs (one or more dogs)

15% of American households have only cats (one or more cats)

10% of American households have dogs and cats (one or more of each)

50% of American households do not have any dogs or cats.

The sample is n=10

a) Probability that exactly 3 have only dogs (p=0.25)

$P(x=3)=\binom{10}{3}0.25^30.75^7=120*0.01563*0.13348=0.25028$

b) Probability that exactly 2 has only cats (p=0.15)

$P(x=2)=\binom{10}{2}0.15^20.85^8=45*0.0225*0.27249=0.2759$

c) Probability that exactly 1 has cats and dogs (p=0.1)

$P(x=1)=\binom{10}{1}0.10^10.90^0=10*0.1*0.38742=0.38742$

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

$P(x=4)=\binom{10}{4}0.50^40.50^6=210*0.0625*0.01563=0.20508$

8 0

3 years ago

If you help me I'll make as brilliant​

If you help me I'll make as brilliant