To find the probability you need to know the number of desired outcomes (i.e. one digit only used) and the total number of outcomes.
In this case there are 3 desired outcomes - 111, 222, 333.
Since any of the 3 positions in the 3-digit number can be any of 3 numbers, there are 3 x 3 x 3 = 27 total possible outcomes.
The probability of having a desired outcome is 3 / 27 = 1 / 9 = 11.1%
Answer:
2x+y=15x+y=10
Consider the first equation. Subtract 15x from both sides.
2x+y−15x=y
Combine 2x and −15x to get −13x.
−13x+y=y
Subtract y from both sides.
−13x+y−y=0
Combine y and −y to get 0.
−13x=0
Divide both sides by −13. Zero divided by any non-zero number gives zero.
x=0
Consider the second equation. Insert the known values of variables into the equation.
15×0+y=10
Multiply 15 and 0 to get 0.
0+y=10
Anything plus zero gives itself.
15 x 21 = 315.
Hope This Helps You!
Good Luck Studying :)
39/40 as a decimal is 0.975
You plug in 3 as s. So ur formula is P=4(3)
P=12 ft