Question

While travelling, john left destination a at 9 am. driving until 7 pm, he travelled a total of 500 miles. the next day, john left at 9 am and drove until 5 pm, covering 270 miles. what was the average speed for both days, while driving?

Answer 1

Answer:

10 hours 500  miles

8 hours 270 miles

_________________

18 hours 770 miles

Average speed: 770 / 18 = 42.77;

Step-by-step explanation:

Answer 2

Answer: 42.78 miles per hour.

Step-by-step explanation:

Given: For first day,

Distance $d_1=500$ miles

Time $t_1=10$ hours

For  next day

Distance $d_2=270$ miles

Time $t_2=8$ hours

For both days,

Total distance = $d_1+d_2=500+270=770$ miles

Total time taken =$t_1+t_2= 10+8=18$hours

Now, the average speed for both days, while driving will be

$\text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}\\\\=\frac{770}{18}=42.7777777778\approx42.78$

Hence, the average speed for both days, while driving = 42.78 miles per hour.