If the variance of the data values in a sample is 121, what is the standard deviation of the data values? A.15 B.12 C.11 D.13

Mathematics

2 answers:

yaroslaw [1]3 years ago

5 0

Answer: 11

Step-by-step explanation:

We know that the standard deviation of a data is square root of variance of the data or we can say variance of a data is square of standard deviation of the data.

Given: Variance of data values = 121

Then the standard deviation of the data values will be given by :-

$\sigma=\sqrt{V}\\\\\Rightarrow\sigma=\sqrt{121}\\\\\Rightarrow\sigma=11$

Hence, If the variance of the data values in a sample is 121, then the standard deviation of the data values will be 11.

miskamm [114]3 years ago

3 0

Variance is standard deviation squared, so in order to find the standard deviation of 121, you would take the square root:
$\sqrt{121} =11$ (c)

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Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10

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Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000 (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

c) Sub set {2, 3, 4, 7, 8, 9} = 0111001110