It is stable if the atom has a full outer shell
Technically, I can't answer the question, because you won't
let me see the picture that goes along with it and is a part of it.
But I'm familiar with the set-up, have dealt with the question before,
and I can answer it from my previous experience and general knowledge.
If there is 500g of mass inside the jar when you lower it over
the candle, then there will be 500g of mass at any time after that,
forever, or until you pick up the jar and take some mass out or put
some more in. It doesn't matter how long you wait. It also doesn't
matter whether or not the candle is burning, whether or not the sun
is shining on the jar, or whether somebody comes along and spray-paints
the outside of the jar with black paint. Matter is not created or destroyed.
Whatever mass was inside when the jar got closed stays in there.
Answer:
Frequency
Explanation:
The property of waves that remains unchanged as it crosses the boundary of one medium to another is the frequency of the wave.
As a wave moves from one boundary to another, the wavelength and the speed of the wave changes.
The speed of the wave is product of wavelength and frequency. Also, the wavelength of the wave is function of the distance between successive crests or troughs of a wave.
The frequency of a wave is the number of waves that crosses a medium per unit of time.
Answer:
A) 8π ft²/ft
B) 24π ft²/ft
C) 48π ft²/ft
Explanation:
Surface area of the spherical balloon is not clear here but it is supposed to be;
S = 4πr²
where:
r is the radius of the spherical balloon
So thus, the rate of change of the surface area of the spherical balloon by its radius will be:
dS/dr = 8πr
A) at r = 1ft;
dS/dr = 8 × π × 1
dS/dr = 8π ft²/ft
B) at r = 3 ft;
dS/dr = 8 × π × 3
dS/dr = 24π ft²/ft
C) at r = 6ft;
dS/dr = 8 × π × 6
dS/dr = 48π ft²/ft
