Answer:
thats alot of people don't you think
Step-by-step explanation:
We need to simplify

First lets factor


=


by applying the radical rule
![\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bab%7D%20%3D%20%20%5Csqrt%5Bn%5D%7Ba%7D%20%5Csqrt%5Bn%5D%7Bb%7D%20)

By applying the radical rule
![\sqrt[n]{x^m} = x^{m/n}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%3D%20x%5E%7Bm%2Fn%7D)
So

=

=

Now let's factor

By applying the radical rule
![\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bab%7D%20%3D%20%20%5Csqrt%5Bn%5D%7Ba%7D%20%20%5Csqrt%5Bn%5D%7Bb%7D%20)
,

So

=

So

=

We know that
![\sqrt[n]{x} = x^{1/n}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B1%2Fn%7D)
so

We now have
We know that
So

We now got

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:

All in All, we get

=

Hope this helps! :D
Answer:
.25 of a liter
Step-by-step explanation:
.2614 of a qt
.53 of a pint
If the value of b is 6 then the system will have an infinite number of solutions since they will be the same lines.