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wel
3 years ago
15

How would the acidic solution affect a clam living in the ocean ? what does a weakened shell mean for the clam​

Biology
1 answer:
kari74 [83]3 years ago
8 0

Answer:

Ocean acidification makes it harder for clams and mussels to find the material they need to build and maintain their calcium carbonate shells. A weakend shell often results in but is not limited to the organisms growing slowly or neededign more food to actually survive if the acidity levels were to increase.

Explanation:

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Now let's look at the specific amino acid interactions at the dimer interface that link the two monomers together into the large
koban [17]

Answer:

Option b) Hydrophobic interactions between phe106 and ile108 of one monomer and ile272 and leu273 of the other monomer. Ionic bonds between arg96 and arg103 of one monomer and glu300 and glu304 of the other monomer.

Explanation:

In the structure, there are ionic hydrogen bonds and salt bridges between the 42, R221, and D24. These interactions have a dynamic impact on the activity and structural stability of the protein nature.

The hydrophobic interactions at the interfaces also contribute in the stabilization of the protein structure.  

3 0
3 years ago
Read 2 more answers
What is the probability that each of the following pairs of parents will produce the indicated offspring? (Assume independent as
ASHA 777 [7]

Answer:

(a) AABBCC × aabbcc->AaBbCc     → 1

(b) AABbCc × AaBbCc->AAbbCC   → 1/32

(c) AaBbCc × AaBbCc->AaBbCc     → 1/8

(d) aaBbCC × AABbcc->AaBbCc    → 1/2

Explanation:

In such cases we calculate the probability of each allelic pair separately.

(a) AABBCC × aabbcc -> AaBbCc  

Aa  Aa   Aa  Aa           Bb  Bb  Bb  Bb         Cc  Cc  Cc  Cc

↓                                   ↓                                ↓  

4/4 = 1                          4/4 = 1                       4/4 = 1    

In case of gene A, out of the 4 probable allelic combinations, 4 will be Aa so the probability is 4/4 = 1.

In case of gene B, out of the 4 probable allelic combinations, 4 will be Bb so the probability is 4/4 = 1.

In case of gene C, out of the 4 probable allelic combinations, 4 will be Cc so the probability is 4/4 = 1.

So, the total probability of getting AaBbCc   = 1 x 1 x 1 = 1.                

(b) AABbCc × AaBbCc -> AA bb CC

AA  AA   Aa  Aa           BB  Bb  Bb  bb         CC  Cc  Cc  cc

↓                                                        ↓           ↓  

2/4                                                    1/4          1/4

In case of gene A, out of the 4 probable allelic combinations, 2 will be AA so the probability is 2/4.

In case of gene B, out of the 4 probable allelic combinations, 1 will be bb so the probability is 1/4.

In case of gene C, out of the 4 probable allelic combinations, 1 will be CC so the probability is 1/4.

So, the total probability of getting AA bb CC = 2/4 x 1/4 x 1/4 = 1/32.

(c) AaBbCc × AaBbCc -> AaBbCc

AA  Aa   Aa  aa           BB  Bb  Bb  bb         CC  Cc  Cc  cc

        ↓                                  ↓                               ↓  

       2/4                               2/4                           2/4

In case of gene A, out of the 4 probable allelic combinations, 2 will be Aa so the probability is 2/4.

In case of gene B, out of the 4 probable allelic combinations, 2 will be Bb so the probability is 2/4.

In case of gene C, out of the 4 probable allelic combinations, 2 will be Cc so the probability is 2/4.

So, the total probability of getting AaBbCc = 2/4 x 2/4 x 2/4 = 1/8.

(d) aaBbCC × AABbcc->AaBbCc

Aa  Aa   Aa  Aa               BB  Bb  Bb  bb          Cc  Cc  Cc  Cc

      ↓                                        ↓                                ↓  

4/4 = 1                                       2/4                          4/4 = 1    

In case of gene A, out of the 4 probable allelic combinations, 4 will be Aa so the probability is 4/4 = 1.

In case of gene B, out of the 4 probable allelic combinations, 2 will be Bb so the probability is 2/4.

In case of gene C, out of the 4 probable allelic combinations, 4 will be Cc so the probability is 4/4 = 1.

So, the total probability of getting AaBbCc = 1 x 2/4 x 1 = 1/2.

5 0
3 years ago
Which of the following is not a source of genetic variation?
Mashcka [7]
<span>the one that is not a source of genetic variation is : D. Asexual reproduction In asexual reproduction, there is no fertilization process between male and female gender. Which mean the offspring that came from asexual reproduction would be exactly the same as its parent, without any chance of genetic variation</span>
5 0
3 years ago
Read 2 more answers
What is the difference between intermolecular and intramolecular forces?
anastassius [24]

Answer:

Intramolecular forces are the forces that hold atoms together within a molecule. Intermolecular forces are forces that exist between molecules.

Explanation:

3 0
3 years ago
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In animal cells, what are the holes between directly connected cells used for intercellular communication called? receptor chemi
Marianna [84]

Answer:

plasmodesmata

Explanation:

Plasmodesmata are channels between adjacent plant cells, while gap junctions are channels between adjacent animal cells. However, their structures are quite different. A tight junction is a watertight seal between two adjacent cells, while a desmosome acts like a spot weld.

8 0
3 years ago
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