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aivan3 [116]
2 years ago
9

Which is a poor conductor of heat a. aluminum b. iron c. ceramic d. zinc

Chemistry
2 answers:
jasenka [17]2 years ago
3 0

Answer:

c. ceramic

Explanation:

because b d and a are metals c is not

TiliK225 [7]2 years ago
3 0
Ceramic is not a metal so ceramic
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Which of the following represents an endothermic reaction?
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Answer:

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The second one would be one of the application of an endothermic reaction as because endothermic reaction always have the heat in the process to mix the reactants and form the products as here in a burning wood when the wood is supplied with heat then it change into products as ashes and smoke fumes So here due to the heat is involved to form the products thats the reaction is endothermic reaction.

Hope it helps

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2 years ago
What electrolyte may fall in level as a result of citrate toxicity from massive transfusion quizlket
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2 years ago
A) 24 g<br> B) 36 g<br> C) 48 g<br> D) 60 g
Hitman42 [59]

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A. 24 g

5 0
2 years ago
What is highly reactive to water and forms an ionic bond with chlorine? It’s very shiny.
34kurt
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3 0
3 years ago
Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t
Vitek1552 [10]

<u>Answer:</u> The mass of decane produced is 1.743\times 10^2g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol

The chemical equation for the hydrogenation of decene follows:

C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = \frac{1}{1}\times 1.225=1.225mol of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g

Hence, the mass of decane produced is 1.743\times 10^2g

5 0
3 years ago
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