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3 years ago

Which is a poor conductor of heat a. aluminum b. iron c. ceramic d. zinc

Chemistry

2 answers:

jasenka [17]3 years ago

3 0

Answer:

c. ceramic

Explanation:

because b d and a are metals c is not

TiliK225 [7]3 years ago

3 0

Ceramic is not a metal so ceramic

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Explain why the electron configuration of 2-3-1 represents an atom in an excited state?

baherus [9]

Answer:

See explanation

Explanation:

If we look at the electron configuration closely, we will discover that the element must have had a ground state electron configuration of 2,4.

This is because, the innermost shell usually holds two electrons while the outer shells hold eight electrons each. The four electrons must be accommodated in the second shell in the ground state configuration of the compound.

However, when the atom is excited, one electron from this shell may move to the third shell to give the excited state configuration 2-3-1 as shown in the question.

6 0

3 years ago

The electrolysis of water forms H2 and O2.

Monica [59]

Answer:

67.5% ≅ 67.6%

Explanation:

Given data:

Mass of water = 17.0 g

Mass of oxygen produced (actual yield)= 10.2 g

Percent yield of oxygen = ?

Solution:

Chemical equation:

2H₂O → 2H₂ + O₂

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 17.0 g/ 18.016 g/mol

Number of moles = 0.944 mol

Now we will compare the moles of oxygen with water to know the theoretical yield of oxygen.

H₂O : O₂

2 : 1

0.944 : 1/2×0.944 = 0.472 mol

Mass of oxygen:

Mass = number of moles× molar mass

Mass = 0.472 mol × 32 g/mol

Mass = 15.104 g

Percent yield:

Percent yield = [Actual yield / theoretical yield] × 100

Percent yield = [ 10.2 g/ 15.104 g] × 100

Percent yield = 0.675 × 100

Percent yield = 67.5%

5 0

3 years ago

Read 2 more answers

Things we take fro, the environment are called..

amm1812

Plants I think or like animals

3 0

3 years ago

If a particular ore contains 55.1 % calcium phosphate, what minimum mass of the ore must be processed to

Diano4ka-milaya [45]

Answer:

6049.69 g or 6.04969 Kg of ore must be processed to get 1 Kg of phosphorous.

Explanation:

Given

An ore has 51% Calcium phosphate

To find

The minimum mass of ore to be processed to get 1.00 Kg of phosphorous

First find the mass of phosphorous in 1 mole = molar mass of Calcium phosphate, Ca₃(PO₄)₃.

Molar mass of Ca₃(PO₄)₃ is 310 g

Molar mass of P is 31 g

1 mole of Ca₃(PO₄)₃ has 3 atoms of phosphorous

i.e 310 g of Ca₃(PO₄)₃ has 3× 31g of P

= 93 g P

93 g P wil be present in 310 g of Ca₃(PO₄)₃

1 Kg or 1000 g of P will be in (1000÷93) ×310

=3333.33 g of Ca₃(PO₄)₃

but the ore has only 55.1% Ca₃(PO₄)₃

i.e

100 g of Ca₃(PO₄)₃ will have 55.1g Ca₃(PO₄)₃

we need 3333.33g of Ca₃(PO₄)₃

100 g of ore will have 55.1g Ca₃(PO₄)₃

3333.33g of Ca₃(PO₄)₃ will be present in

(3333.33÷ 55.1) ×100

= 6049.60 g of the ore

So 6049.69 g or 6.04969 Kg of ore must be processed to get 1 Kg of phosphorous.

3 0

3 years ago

Which of the following are acceptable ways to represent an isotope of carbon?

qaws [65]

My best guess is a. carbon-10
I just learned about it yesterday hope it help :)

3 0

4 years ago