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professor190 [17]
2 years ago
14

Calculate the empirical formula of a compound that is 56.27% phosphorus and the remainder is oxygen.

Chemistry
1 answer:
Inessa [10]2 years ago
5 0

Answer:

ikjnfjngvfnjfdkmldskmofevivrtbhurt3gdkjbfongidfngherghihierihgdifngodfnvgndfugiripegndbjgindgndfvcl vncf 'g

Explanation:

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A sample of the mineral hematite Iron (III) oxide has a mass of 12.4g. How many moles of the mineral are present?
8090 [49]

Thus problem is providing us with the mass of iron (III) oxide as 12.4 g so the moles are required and found to be 0.0776 mol after the calculations:

<h3>Mole-mass relationships:</h3>

In chemistry, we use mole-mass relationships in order to calculate grams from moles and vice versa. In this case, since we are given the mass of iron (III) oxide as 12.4 g one can calculate the moles by firstly quantifying its molar mass:

Fe_2O_3\rightarrow 2*55.85 g/mol+3*16.00 g/mol=159.7g/mol

Then, we prepare a conversion factor in order to cancel out the grams and thus, get moles:

12.4gFe_2O_3*\frac{1molFe_2O_3}{159.7gFe_2O_3} \\\\=0.0776molFe_2O_3

Learn more about mole-mass relationships: brainly.com/question/18311376

8 0
2 years ago
You perform a combustion analysis on a 255 mg sample of a substance that contains only C, H, and O, and you find that 561 mg of
zhuklara [117]
The combustion of an organic compound is mostly written as,
                        CaHbOc + O2 --> CO2 + H2O
where a, b, and c are supposed to be the subscripts of the elements C, H, and O in the compound. Determining the number of moles of C and H in the product which is the same as that in the compound,
   (Carbon, C)   :   (561 mg) x (12/44) = 153 mg x (1 mmole/12 mg) = 12.75
   (Hydrogen, H) :  (306 mg) x (2/18)  = 34 mg x (1 mmole/1 mg) = 34 
   Calculating for amount of O in the sample,
(oxygen, O) = 255 - 153 mg - 34 mg = 68 mg x (1mmole/16 mg) = 4.25 
The empirical formula is therefore,
                        C(51/4)H34O17/4
                           C3H8O1
The molar mass of the empirical formula is 60. Therefore, the molecular formula of the compound is,
                                C9H24O3
5 0
3 years ago
Read 2 more answers
What is the noble gas configuration for telleurium
Maru [420]

[Kr] 4d10 5s2 5p4 is the noble gas configuration for telleurium because of the presence of different number of electrons.

<h3>What is telleurium?</h3>

Tellurium is a noble gas element that is non-reactive in nature due to complete outermost shell. It has atomic number of 52 which means that it has 52 number of electrons.

So we can conclude that [Kr] 4d10 5s2 5p4 is the noble gas configuration for telleurium because of the presence of different number of electrons.

Learn more about noble gas here: brainly.com/question/13715159

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2 years ago
PLEASE ANSWER
zhuklara [117]
D) light is reflecting in the direction indicated by T.
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3 years ago
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Which statement is true when considering color in a fiber?
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The color is an effect as a result of different wavelengths and frequencies of the light waves. So, color is a property of an object that depends on the wavelength.  From all the given statements the following is true: T<span>he color depends upon the lighting source. More precisely, the color depends upon the wavelength of the lighting source.</span>
5 0
3 years ago
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