Answer:
i mean kinda they should throw people in the air tho lol
Explanation:
It takes exactly 500 seconds for the sun's radiation to reach the earth or about 8 minutes (8.333333333333... to be exact). Just divide 150 million km by 300,000 km/s. Hope this helps
Answer:
Ok so, b. A redox reaction occurs in an electrochemical cell, where silver (Ag) is oxidized and nickel (Ni) is reduced - In voltaic cells, also called galvanic cells, oxidation occurs at the anode and reduction occurs at the cathode. A mnemonic for this is "An Ox. Red Cat." So since silver is oxidized, the silver half-cell is the anode. And the nickel half-cell is the cathode...
i. Write the half-reactions for this reaction, indicating the oxidation half-reaction and the reduction half-reaction- The substance having highest positive  potential will always get reduced and will undergo reduction reaction. Here, zinc will always undergo reduction reaction will get reduced
ii. Which metal is the anode, and which is the cathode?-The anode is where the oxidation reaction takes place. In other words, this is where the metal loses electrons. The cathode is where the reduction reaction takes place.
iii. Calculate the standard potential (voltage) of the cell
Look up the reduction potential,
E
⁰
red
, for the reduction half-reaction in a table of reduction potentials
Look up the reduction potential for the reverse of the oxidation half-reaction and reverse the sign to obtain the oxidation potential. For the oxidation half-reaction,
E
⁰
ox
=
-
E
⁰
red
.
iv. What kind of electrochemical cell is this? Explain your answer.
All parts in the electrochemical cells are labeled in second figure. Following are the part in electrochemical cells
1) Anode 2) Cathode 3) gold Stripe (Electrode) 4) Aluminium Glasses (Electrode) 5) Connecting wires 6) Battery
Explanation:
Answer : The equilibrium concentration of
in the trial solution is 
Explanation :
First we have to calculate the initial moles of
and
.

and,

The given balanced chemical reaction is,

Since 1 mole of
reacts with 1 mole of
to give 1 mole of 
The limiting reagent is, 
So, the number of moles of
= 0.0020 mmole
Now we have to calculate the concentration of
.

Using Beer-Lambert's law :
where,
A = absorbance of solution
C = concentration of solution
l = path length
= molar absorptivity coefficient
and l are same for stock solution and dilute solution. So,

For trial solution:
The equilibrium concentration of
is,
![[SCN^-]_{eqm}=[SCN^-]_{initial}-[FeSCN^{2+}]](https://tex.z-dn.net/?f=%5BSCN%5E-%5D_%7Beqm%7D%3D%5BSCN%5E-%5D_%7Binitial%7D-%5BFeSCN%5E%7B2%2B%7D%5D)
= 0.00050 M
Now calculate the
.

Now calculate the concentration of
.
![[SCN^-]_{eqm}=[SCN^-]_{initial}-[FeSCN^{2+}]](https://tex.z-dn.net/?f=%5BSCN%5E-%5D_%7Beqm%7D%3D%5BSCN%5E-%5D_%7Binitial%7D-%5BFeSCN%5E%7B2%2B%7D%5D)
![[SCN^-]_{eqm}=(0.00050M)-(9.17\times 10^{-5}M)](https://tex.z-dn.net/?f=%5BSCN%5E-%5D_%7Beqm%7D%3D%280.00050M%29-%289.17%5Ctimes%2010%5E%7B-5%7DM%29)
![[SCN^-]_{eqm}=4.58\times 10^{-8}M](https://tex.z-dn.net/?f=%5BSCN%5E-%5D_%7Beqm%7D%3D4.58%5Ctimes%2010%5E%7B-8%7DM)
Therefore, the equilibrium concentration of
in the trial solution is 
Answer:
There are multiple ways to check mass but I'll tell you one. Look below
Explanation:
One easy way of checking atomic mass is by adding protons and neutrons.
For example:
We have 5 protons and 4 neutrons.
5+4=9
I hope this helps (: