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3 years ago

Complete the following equation: 250/96Cm ——-> ? + 4 1/0n

Chemistry

1 answer:

vfiekz [6]3 years ago

3 0

Answer:

²⁵⁰₉₆Cm → ²⁴⁶₉₆Cm + 4 ¹₀n

Explanation:

The complete equation is;

²⁵⁰₉₆Cm → ²⁴⁶₉₆Cm + 4 ¹₀n

The above equation is an example of a nuclear reaction in which unstable atom of Cm emits neutrons to become more stable.
Radioactive isotopes undergo radioactivity or decay to attain stability, they do so by emitting particles such as alpha, beta particles or a neutron.
An atom of Cm-250 undergoes decay and emits four neutrons to form an atom of Cm-246.

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1. Why is it important to accurately predict the possible formation and path of a hurricane?

ad-work [718]

1) Prediction of a hurricane's path/formation can save lives, since we can predict the strength, then warn the people who are in danger of it's reach.

4) The more wind a hurricane has, usually the faster it tears apart, since the strong winds acts to constrict the center, limiting and sometimes altogether stopping the hurricane.

5) I'd say yes, since the humidity is really high, so the wind can whip that up into the heat, then the hot air descends to create a vortex.

7 0

3 years ago

Read 2 more answers

The product of the nuclear reaction in which 40Ar is subjected to neutron capture followed by alpha emission is ________. The pr

Orlov [11]

Answer:

37S

Explanation:

Radioactivity is the spontaneous emission of particles and / or electromagnetic radiation by unstable atomic nuclei leading to their disintegration.

We have two main types of radioactivity: radioactive decay and artificial transmutation.

In radioactive decay ( natural radioactivity ), a naturally occurring radioactive element like Uranium-238 disintegrates or decays into more stable isotopes with the emission of particles and/or radiation.

23892U = 23490Th + 42He

Artificial transmutation is the collision of two particles where one particle captures the other used to bombard it. There is subsequent production of isotopes similar or different from the bombarded particle. Neutrons, alpha particles ( helium nucleus ), electrons, protons can be used to bombard elements.

147N + 42He = 178O + 11P

For the above question which is artificial transmutation, the reaction equation is

4018Ar + 10n = 3716S + 42He

So, the neutron capture by Argon-40 will produce a radioisotope Sulphur-37 with the emission of an alpha particle.

5 0

3 years ago

Which ions have ten electrons in the outermost subshell?

SVEN [57.7K]

Explanation:

There are ten d electrons in the outermost d subshell for Zn2+.

8 0

3 years ago

How many seconds are required to produce 4.00 g of aluminum metal from the electrolysis of molten alcl3 with an electrical curre

Brilliant_brown [7]

The correct answer is e. 3.57×10³
Al³+(aq) + 3e→AL(s)
4.00g of AL=4g/26.98 g/mol= 0.1483 mol
t=znF/1 where t is time in seceonds.
Z= valency number of ions of the substance or electrons which are transferred per ion
F= Faraday's constant
I = electric current in'A'CA C/s
t=(3×0.1483 mol ×96485 C/mol) /12(C15)
t=3577 second = 3.5 ×10³s

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3 years ago

A 80.0 g piece of metal at 88.0°C is placed in 125 g of water at 20.0°C contained in a calorimeter. The metal and water come to

grandymaker [24]

Answer:

The specific heat of the metal is 0.485 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of the piece of metal = 80.0 grams

Mass of the water = 125 grams

Initial temperature of the metal = 88.0 °C

Initial temperature of water =20.0 °C

Final temperature = 24.7 °C

pecific heat of water is 4.18 J/g*°C

<u>Step 2:</u> Calculate specific heat of the metal

Qgained = -Qlost

Q =m*c*ΔT

Qwater = - Qmetal

m(water)*c(water)*ΔT(water) = -m(metal)*c(metal)*ΔT(metal)

with mass of water = 125 grams

with c( water) = 4.18 J/g°C

with ΔT(water) = T2-T1 = 24.7 - 20 = 4.7°C

with mass of metal = 80.0 grams

with c(metal) = TO BE DETERMINED

with ΔT(metal) = 24.7 - 88.0 = -63.3 °C

125*4.18*4.7 = -80 * C(metal) * -63.3

2455.75 = -80 * C(metal) * -63.3

C(metal) = 2455.75 / (-80*-63.3)

C(metal) = 0.485 J/g°C

The specific heat of the metal is 0.485 J/g°C

3 0

4 years ago