Answer and explanation :
Fluid distribution is a new technique to produce and to transmit power from one place to other its play a major role in power distribution it is a process of using fluid (any type of fluid as oil or water ) under pressure to generate to control or to transmit
fluid power system is divided into two types
- Hydraulic fluid power system
- pneumatic fluid power system
Answer:
I. 3.316 kW
II. 1.218 kW
III. 2.72
Explanation:
At state 1, the enthalpy and entropy are determined using the given data from A-13.
At P1 = 200kpa and T1 = 0,
h1 = 253.07 kJ/kg
s1 = 0.9699 kJ/kgK
At state 2, the isentropic enthalpy is determined at P2 = 1400kpa and s1 = s2 by interpolation. Thus
h2(s) = 295.95 kJ/kg
The actual enthalpy is then gotten by
h2 = h1 + [h2(s) - h1]/n
h2 = 253.07 + [295.95 - 253.07]/0.88
h2 = 253.07 + 48.73
h2 = 301.8 kJ/kg
h3 = h4 = 120.43 kJ/kg
Heating load is determined from energy balance, thus,
Q'l = m'(h1 - h4)
Q'l = 0.025(253.07 - 120.43)
Q'l = 0.025 * 132.64
Q'l = 3.316 kW
Power is determined by using
W' = m'(h2 - h1)
W'= 0.025(301.8 - 253.07)
W'= 0.025 * 48.73
W'= 1.218 kW
The Coefficient Of Performance is Q'l / W'
COP = 3.316/1.218
COP = 2.72
Answer:
Explanation:
the shape on of the earth
Answer:
There are n types of coupons. Each newly obtained coupon is, independently, type i with probability p i , i = 1,...,n. Find the expected number and the variance of the number of distinct types obtained in a collection of k coupons
Explanation: The solution for the expectation has already been given in the comments. The calculation is slightly simplified by considering the number. Y= n-X of coupon types not collected with E[X] =N-E[Y] and Var(X) = Var(Y). Let Yi denote the indicator variable
Type i is not obtained, its expectations is the probability (1-pi)^k
Of not obtaining a coupon of type i, so the expected number of coupons is not obtained is
E[Y]= E{£iYi}= Ei(1-pi)^k
The variance is calculated analogously by expressing in terms of expectation,
Var(Y)=E{[EiYi]}^2-E[EiYi]^2
= Ei(1-pi)^k(1-(1-pi)^k + Ei=/j(1-pi-pj)^k-(1-pi)^k(1-pj)^k