Answer:
(a): The launch velocity is Vx= 666.66 m/s.
(b): The angle wich the projectile contacts the ground is α= 0.38°
Explanation:
h= 1m
g= 9.8 m/s²
h= g*t²/2
t= 0.45 s
Vy= g*t
Vy= 4.42 m/s
d=Vx* t
Vx= 666.66 m/s (a)
α= tg⁻¹ ( Vy/Vx)
α= 0.38° (b)
The classical motion for an oscillator that starts from rest at location x₀ is
x(t) = x₀ cos(ωt)
The probability that the particle is at a particular x at a particular time t
is given by ρ(x, t) = δ(x − x(t)), and we can perform the temporal average
to get the spatial density. Our natural time scale for the averaging is a half
cycle, take t = 0 → π/
ω
Thus,
ρ = 
Limit is 0 to π/ω
We perform the change of variables to allow access to the δ, let y = x₀ cos(ωt) so that
ρ(x) = 
Limit is x₀ to -x₀

Limit is -x₀ to x₀

This has
as expected. Here the limit is -x₀ to x₀
The expectation value is 0 when the ρ(x) is symmetric, x ρ(x) is asymmetric and the limits of integration are asymmetric.
B. to achieve sustainable development
Answer:
correct option is (A) 0.5
Explanation:
given data
axial column load = 250 kN per meter
footing placed = 0.5 m
cohesion = 25 kPa
internal friction angle = 5°
solution
we know angle of internal friction is 5° that is near to 0°
so it means the soil is almost cohesive soil.
and for a pure cohesive soil
= 0
and we know formula for
is
= (Nq - 1 ) × tan(Ф) ..................1
so here Ф is very less
should be nearest to zero
and its value can be 0.5
so correct option is (A) 0.5
Answer:
- 3/5" = 12'
- 1 3/4" = 35'
- 1 1/4" = 25'
- 9/10" = 18'
- 2 13/20" = 53'
Explanation:
One number is wrong; they all lack units.
The basic ratio is 1" = 20', so you can divide feet by 20 to find inches.
- 3/5" = 12'
- 1 3/4" = 35'
- 1 1/4" = 25'
- 9/10" = 18'
- 2 13/20" = 53'
Perhaps you want decimal inches:
- 0.60" = 12'
- 1.75" = 35'
- 1.25" = 25'
- 0.90" = 18'
- 2.65" = 53'