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belka [17]
3 years ago
9

Which option distinguishes the step in the requirements engineering process described in the following scenario?

Engineering
2 answers:
boyakko [2]3 years ago
3 0

Answer:

b

Explanation:

Ivan3 years ago
3 0

Answer:

Write engineering requirements

Explanation:

Engineering requirements  - a detailed and measurable description of what a product should do to meet a customer need

Engineering requirements are a technical interpretation that put customer needs into measurable specifications and values such as; size, quantity, weight, and time.

And it is the denotive definition of the question

- massmaster34

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A projectile is launched horizontally 1m above the ground. If it lands 300m away from the initial launch position, find: a)-the
PIT_PIT [208]

Answer:

(a): The launch velocity is Vx= 666.66 m/s.

(b): The angle wich the projectile contacts the ground is α= 0.38°

Explanation:

h= 1m

g= 9.8 m/s²

h= g*t²/2

t= 0.45 s

Vy= g*t

Vy= 4.42 m/s

d=Vx* t

Vx= 666.66 m/s (a)

α= tg⁻¹ ( Vy/Vx)

α= 0.38° (b)

4 0
3 years ago
Find an expectation value in the n th state of the harmonic oscillator.Find an expectation value in the n th state of the harmon
s344n2d4d5 [400]

The classical motion for an oscillator that starts from rest at location x₀ is

                                           x(t) = x₀ cos(ωt)

The probability that the particle is at a particular x at a particular time t

is given by ρ(x, t) = δ(x − x(t)), and we can perform the temporal average

to get the spatial density. Our natural time scale for the averaging is a half

cycle, take t = 0 → π/ ω

Thus,

ρ =   \frac{1}{\pi / w} \int\limits^\pi_0 {d(x - x_o cos(wt))} \, dt

Limit is 0 to π/ω

We perform the change of variables to allow access to the δ, let y = x₀ cos(ωt)  so that

ρ(x) = -\frac{w}{\pi } \int\limits^x_x {\frac{d ( x - y)}{x_ow sin(wt)} } \, dy

Limit is x₀ to -x₀

\frac{1}{\pi } \int\limits^x_x {\frac{d (x-y)}{x_o\sqrt{1 - cos^2(wt)} } } \, dy

Limit is -x₀ to x₀

= \frac{1}{\pi } \int\limits^x_x {\frac{d(x-y)}{\sqrt{x_o^2 - y^2} } } \, dy\\ \\= \frac{1}{\pi\sqrt{x_o^2 - x^2}  }

This has \int\limits^x_x {p(x)} \, dx  = 1 as expected. Here the limit is -x₀ to x₀

The expectation value is 0 when the ρ(x) is symmetric, x ρ(x) is asymmetric and the limits of integration are asymmetric.

6 0
4 years ago
How do we need to prepare for the future?
Paraphin [41]
B. to achieve sustainable development
5 0
3 years ago
A 1 m wide continuous footing is designed to support an axial column load of 250 kN per meter of wall length. The footing is pla
creativ13 [48]

Answer:

correct option is (A) 0.5

Explanation:

given data

axial column load = 250 kN per meter

footing placed =  0.5 m

cohesion = 25 kPa

internal friction angle =  5°

solution

we know angle of internal friction is 5° that is near to 0°

so it means the soil is almost cohesive soil.

and for  a pure cohesive soil

N_{\gamma } = 0

and we know formula for N_{\gamma } is

N_{\gamma } = (Nq - 1 ) × tan(Ф)   ..................1

so here Ф is very less  N_{\gamma } should be nearest to zero

and its value can be 0.5

so correct option is (A) 0.5

7 0
4 years ago
Help please all of the numbers b4 the equal sign are wrong
Nostrana [21]

Answer:

  • 3/5" = 12'
  • 1 3/4" = 35'
  • 1 1/4" = 25'
  • 9/10" = 18'
  • 2 13/20" = 53'

Explanation:

One number is wrong; they all lack units.

The basic ratio is 1" = 20', so you can divide feet by 20 to find inches.

  • 3/5" = 12'
  • 1 3/4" = 35'
  • 1 1/4" = 25'
  • 9/10" = 18'
  • 2 13/20" = 53'

Perhaps you want decimal inches:

  • 0.60" = 12'
  • 1.75" = 35'
  • 1.25" = 25'
  • 0.90" = 18'
  • 2.65" = 53'
7 0
3 years ago
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