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3 years ago

Gold and silver rings can receive an arc and turn molten. True or False

Engineering

2 answers:

liubo4ka [24]3 years ago

8 0

The answer is False!
The answer is false

atroni [7]3 years ago

6 0

Answer:

true

Explanation:

I put false on a test and it was wrong

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In order to keep an automobile operating, it is necessary to keep adding fuel as it is used up. Explain why this doesn't contrad

Semmy [17]

Answer:

There is conversion of energy from one form to another and this justifies the law of conservation of energy, which states that energy can neither be created nor destroyed but can be converted from one form to another.

Explanation:

The fuel added to automobile is a chemical energy, which provides thermal energy of the combustion engine of the automobile, which is then converted to mechanical energy of the moving parts of the automobile. Thus, there is conversion of energy from one form to another. This justifies the law of conservation of energy, which states that energy can neither be created nor destroyed but can be converted from one form to another.

3 0

2 years ago

An excited electron in an Na atom emits radiation at a wavelength 589 nm and returns to the ground state. If the mean time for t

11Alexandr11 [23.1K]

Answer: Inherent width in the emission line: 9.20 × 10⁻¹⁵ m or 9.20 fm

length of the photon emitted: 6.0 m

Explanation:

The emitted wavelength is 589 nm and the transition time is ∆t = 20 ns.

Recall the Heisenberg's uncertainty principle:-

∆t∆E ≈ h ( Planck's Constant)

The transition time ∆t corresponds to the energy that is ∆E

$E=h/t = \frac{(1/2\pi)*6.626*10x^{-34} J.s}{20*10x^{-9} } = 5.273*10x^{-27} J = 3.29* 10^{-8} eV$ .

The corresponding uncertainty in the emitted frequency ∆v is:

∆v= ∆E/h = (5.273*10^-27 J)/(6.626*10^ J.s)= 7.958 × 10^6 s^-1

To find the corresponding spread in wavelength and hence the line width ∆λ, we can differentiate

λ = c/v

dλ/dv = -c/v² = -λ²/c

Therefore,

∆λ = (λ²/c)*(∆v) = {(589*10⁻⁹ m)²/(3.0*10⁸ m/s)} * (7.958*10⁶ s⁻¹)

= 9.20 × 10⁻¹⁵ m or 9.20 fm

The length of the photon (<em>l)</em> is

l = (light velocity) × (emission duration)

= (3.0 × 10⁸ m/s)(20 × 10⁻⁹ s) = 6.0 m

6 0

3 years ago

When the electrical connection to the alternator from the battery is not tight, it can cause?

Oksi-84 [34.3K]

Answer:

affects the flow of electricity

Explanation:

A loose battery terminal affects the flow of electricity. There is less power going to the electrical systems and the vehicle will not start or start sluggishly. Also, a loose battery terminal causes the car's electrical components like navigation, car lights, and audio among others to dim or fail completely.

3 0

2 years ago

Create a program, using at least one For Loop, that displays the Sales Amounts in each of 4 regions during a period of three mon

kari74 [83]

Answer:

C++ code explained below

Explanation:

/*C++ program that prompts sales for four regions of three sales and prints

the sales values to console */

#include<iostream>

#include<iomanip>

#include<cstring>

using namespace std;

int main()

{

//set constant values

const int SALES=3;

const int REGIONS=4;

//create an array of four regions

string regionNames[]={"Region 1","Region 2","Region 3","Region 4"};

//create a 2D array to read sales

int sales[REGIONS][SALES];

//read sales for four regions

for(int region=0;region<REGIONS;region++)

{

cout<<regionNames[region]<<endl;

for(int sale=0;sale<SALES;sale++)

{

cout<<"Enter sales ";

cin>>sales[region][sale];

}

//print sales

for(int region=0;region<REGIONS;region++)

{

cout<<regionNames[region]<<"-";

for(int sale=0;sale<SALES;sale++)

{

cout<<setw(5)<<sales[region][sale];

}

cout<<endl;

}

//pause program output on console

system("pause");

return 0;

}

5 0

3 years ago

Part of a control linkage for an airplane consists of a rigid member CB and a flexible cable AB Originally the cable is unstretc

AnnZ [28]

Answer:

$e_{ab} = 4.18*10^(-3)$

Explanation:

This question will be solved with the help of diagram (see attachment)

Given:

Δ∅ = 0.50 degrees (correction)

BC = 800 mm

AC = 600 mm

Solution:

We use coordinate system with point C as origin (0,0)

Hence,

Point A = (600,0)

Point B = (0,800)

The change in length or displacement can be calculated BB' :

BB' = BC * tan (Δ∅) = (800 mm) * tan (0.5) = 6.9815 mm

Hence, Point B' = (-6.9815,800) and we calculate distance A and B

$AB = \sqrt{600^2 + 800^2} = 1000 mm$

We calculate distance A and B'

$AB' = \sqrt{(600 - (-6.9815))^2 + (0-800)^2} = 1004.2 mm$

Normal Strain in AB is:

$e_{ab} = \frac{AB' - AB}{AB} \\\\= \frac{1004.2 - 1000}{100}\\\\= 4.18 * 10^(-3)$

The solution is :

$e_{ab} = 4.18 * 10^(-3)$

6 0

2 years ago