T(1/2)=1/(k[NO2])
[NO2]=1/(kt(1/2))
[NO2]=1/(0.54M-1 s-1*22s) seconds cancel
[NO2]=1/11.88=0.0842
inital mole= 0.0842*volume(2.5)=0.210 mols
Since the temperature
is a constant, we can use Boyle's law to solve this.<span>
<span>Boyle' law says "at a constant temperature, the
pressure of a fixed amount of an ideal gas is inversely proportional to its
volume.
P α 1/V
</span>⇒
PV = k (constant)<span>
Where, P is the pressure of the gas and V is the
volume.
<span>Here, we assume that the </span>gas in the balloon is an ideal gas.
We can use Boyle's law for these two situations as,
P</span>₁V₁ = P₂V₂<span>
P₁ = 100.0 kPa = 1 x 10⁵ Pa
V₁ =
3.3 L
P₂ =
90.0 x 10³ Pa
V₂ =?
By substitution,
1 x 10⁵ Pa x 3.3 L = 90 x 10³ Pa x V₂</span><span>
V</span>₂ = 3.7 L<span>
</span><span>Hence, the volume of gas when pressure is 90.0 kPa
is 3.7 L.</span></span>
Cu (s) + 2AgNO3 ---> 2Ag + Cu(NO3)2
=13.5 moles Silver Nitrate
2,8,1
It's in group 1, so its outershell only has 1 electron, and the other shells are completely filled, so 2 then 8. :)
<span>sunspots, hope this helps!!!!</span>
