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il63 [147K]
2 years ago
9

Let's repeat this process for the atoms that make up the substances that do not conduct when dissolved in water. What do you not

ice now?
Chemistry
1 answer:
bulgar [2K]2 years ago
3 0

Answer:

Explanation:

If they do not disolve in water they are non electrolyte and hence will not conduct eletricity. If you had a lab where a batter was supplying power and the wire carryin the electricity went through a water bath if the water was pure and nothing disolved in it the light would not turn on but if you added something like salt it would conduct the electricity

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What is the mass of 203 ml of a liquid that has a density of 0.680 g/ml?
kobusy [5.1K]
Mass = density* volume

Mass  =  0.680 *  203

MASS = 138.04
3 0
3 years ago
WHat are the 7 parts of the water cycle
LiRa [457]
The 7 parts of the water cycle would be precipitation runoff evaporation condensation than precipitation again and runoff again 3>
3 0
3 years ago
The temperature of a sample of gas in steel container at 30.3 Atm is
vladimir1956 [14]

Answer:

74.09 atm

Explanation:

Using the gas laws ( Charles and Boyle's law). We have the formula ,

P1/T1 = P2/T2

Where P1 = 30.3atm

T1 = -100 degree Celsius

to kelvin = -100+ 273 = 173K

T2 = 150 degree Celsius

To Kelvin = 150 = 150+273 = 423K

Imputing values

P1/T1 = P2/T2

30.3/173 = P2/ 423

Cross multiply

173×P2 = 30.3 ×423

173P2 = 12816.9

Divide both sides by 173

P2 = 12816.9/173

P2 = 74.09 atm

I hope this was helpful, please mark as brainliest

6 0
3 years ago
Read 2 more answers
What is the maximum number of electrons in an atom n=4 l=1 ml=0
Nitella [24]

Answer:

18 electrons

Explanation:

when l=1, this tell you that it is "p sub shell"

4 0
2 years ago
How many kJ of heat are released by the reaction of 25.0 g of Na2O2(s) in the following reaction? (M = 78.0 g/mol for Na2O2)
solong [7]

-20.16 KJ of heat are released by the reaction of 25.0 g of Na2O2.

Explanation:

Given:

mass of Na2O2 = 25 grams

atomic mass of Na2O2 = 78 gram/mole

number of mole = \frac{mass}{atomic mass of 1 mole}

                          = \frac{25}{78}

                          =0. 32 moles

The balanced equation for the reaction:

2 Na2O2(s) + 2 H2O(l) → 4 NaOH(aq) + O2(g) ∆Hο = −126 kJ

It can be seen that 126 KJ of energy is released when 2 moles of Na2O2 undergoes reaction.

similarly 0.3 moles of Na2O2 on reaction would give:

\frac{126}{2} = \frac{x}{0.32}

x = \frac{126 x 0.32}{2}

 = -20.16 KJ

Thus, - 20.16 KJ of energy will be released.

6 0
3 years ago
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