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3 years ago

Formula:

Physics

1 answer:

s2008m [1.1K]3 years ago

8 0

Answer:

55N

Explanation:

Using Newton's second law of motion:

F=ma

Force=mass × acceleration

F=25×2.2

F=55N

So 55 Newtons are needed

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When a potential difference of 12 V is applied to a wire 6.7 m long and 0.31 mm in diameter the result is an electric current of

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The wire needs to be sauderwired to be connected back into place to get energy into column so it came function properly again!

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3 years ago

How far does Andre have to push a box to do 430 J of work, if he applies a force of 15 Newtons

kap26 [50]

Answer:

28.7m

Explanation:

Given parameters;

Work done = 430J

Force applied = 15N

Unknown:

Distance moved = ?

Solution:

Work done is the force applied to move a body through a certain distance.

Work done = Force x distance

So;

430 = 15 x distance

Distance = 28.7m

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3 years ago

During their physics field trip to the amusement park, Tyler and Maria took a rider on the Whirligig. The Whirligig ride consist

blondinia [14]

Answer:

Speed = 7.04434 m/s

Explanation:

Given that:

The radius of the circle = 6.5 m

The expression for the calculation of circumference is shown below as:

$Circumference=2\times \pi \times radius$

Thus,

$Circumference=2\times \frac{22}{7} \times 6.5\ m=40.8572\ m$

Time taken = 5.8 seconds.

Thus, The speed is:

$Speed=\frac{Circumference}{Time\ Taken}$

So,

$Speed=\frac{40.8572}{5.8}\ m/s$

<u>Speed = 7.04434 m/s</u>

8 0

4 years ago

Read 2 more answers

A professional racecar driver buys a car that can accelerate at 5.9 m/s2. The racer decides to race against another driver in a

3241004551 [841]

Answer:

(a) Time will be t = 3.56 sec

(b) Distance traveled by car when they are side by side is 37.38712 m

(b) Velocity of race car = 21.004 m/sec

velocity of stock car = 12.816 m/sec

Explanation:

We have given acceleration of the car $a_1=5.9m/sec^2$

Acceleration of the stock car $a_2=3.6m/sec^2$

When 1st car overtakes the second car then distance traveled by both the car will be same

(a) So $s_1=s_2$

As both car starts from rest so initial velocity of both car will be 0 m/sec

It is given that stock car leaves 1 sec before

So $\frac{1}{2}\times 5.9\times t^2=\frac{1}{2}\times (t+1)^2\times 3.6$

After solving t = 3.56 sec

(b) From second equation of motion $s=ut+\frac{1}{2}at^2=0\times 3.56+\frac{1}{2}\times 5.9\times 3.56^2=37.38712m$

So velocity of race car v = 0+5.9×3.56 = 21.004 m/sec

Velocity of stock car v = 0+ 3.6×3.56 = 12.816 m/sec

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4 years ago

Which direction do electrons travel

Sedaia [141]

Answer:

option a negative to positive

Explanation:

The flow of electrons is termed electron current. Electrons flow from the negative terminal to the positive. Conventional current or simply current, behaves as if positive charge carriers cause current flow. Conventional current flows from the positive terminal to the negative

brainliest plsss

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3 years ago