A compass would work differently on the moon than the Earth because Earth's magnetic field is between 25,000 and 65,000 NanoTeslas. Whereas, the Moons magnetic field is about 2,500-6,500 and some parts of the moon have nonexistent magnetic fields.
Answer:
The magnitude of the net electric field is:
Explanation:
The electric field due to q1 is a vertical positive vector toward q1 (we will call it E1).
On the other hand, the electric field due to q2 is a horizontal positive vector toward q2(We will call it E2).
Knowing this, the <u>magnitude of the net electric</u> field will be the<u> E1 + E2. </u>
Let's find first E1 and E2.
The electric field equation is given by:
Where:
- k is the Coulomb constant (k = 9*10^{9} Nm²/C²)
- q1 is the first charge
- d1 is the distance from q1 to P
And E2 will be:
Finally, we need to use the Pythagoras theorem to find the magnitude of the net electric field.
I hope it helps you!
2nd and third laws of energy
Answer:
80.6 mV
Explanation:
Parameters given:
Number of turns, N = 115
Radius of coil, r = 2.71 cm = 0.0271m
Time taken, t = 0.133s
Initial magnetic field, Bin = 50.1 mT = 0.0501 T
Final magnetic field, Bfin = 90.5 mT = 0.0905 T
Induces EMF is given as:
EMF = [(Bfin - Bin) * N * A] / t
EMF = [(0.0905 - 0.0501) * 115 * pi * 0.0271²] / 0.133
EMF = (0.0404 * 115 * 3.142 * 0.0007344) / 0.133
EMF = 0.0806 V = 80.6 mV
Answer:
I'm not 100% sure tbh but the only thing I think makes sense to represent vibration would be frequency which is measure in Hertz (Hz)
Explanation:
