By applying the second equation of motion, the speed at which he threw the second stone is equal to 12.10 m/s.
<h3>How to determine the speed?</h3>
First of all, we would calculate the time taken by the first stone to reach a height of 49 meters by applying the second equation of motion as follows:
S = ut + ½gt²
49 = 0(t) + ½ × 9.8 × t²
49 = 4.9t²
t² = 49/4.9
t = √10
t = 3.16 seconds.
Now, we can determine the speed at which he threw the second stone:
<u>Note:</u> Time = 3.16 - 1 = 2.16 seconds.
S = ut + ½gt²
49 = u(2.16) + ½ × 9.8 × 2.16²
49 = 2.16u + 22.86
2.16u = 49 - 22.86
u = 26.14/2.16
u = 12.10 m/s.
Read more on initial speed here: brainly.com/question/19365526
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Answer: 90 meters
Explanation: 60/20=3 and 3*30=90 so it is 90 meters.
Answer:
the distance of image from the vertex is 45 cm and the image formed is in the glass.
Explanation:
distance of object, u = - infinity
radius of curvature, R = - 15 cm
refractive index, n = 1.5
Let the distance of image is v.
Use the formula
The image is in the glass.
The circuit has to be closed so current flows.
Answer:
Explanation:
According to newton's law , force between mass m₁ and m₂ at distance x is given by the following expression
F = G m₁m₂ / x²
differentiating F with respect to x , we have
dF / d x = ₋2G m₁m₂ / x³ .
Rate of reduction of force ∝ 1 / x³
