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3 years ago

Find the area of the square on this centimetre grid

Mathematics

1 answer:

Bess [88]3 years ago

6 0

Answer:

Step-by-step explanation:

the perfect square count as 1

the half square or the triangle count as half

then u got it bro

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A restaurant sells 33 bowls of soup every 3 days. At this rate, about how many bowls of soup can the restaurant sell in 7 days?

Verizon [17]

Answer:

77 bowls of soup

Step-by-step explanation:

if you divide 33 bowls by 3 days, you find that they sell 11 bowls of soup per day. multiply 11 by the 7 days to find that they sell 77 bowls of soup.

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3 years ago

What is 16/20 simplified

Digiron [165]

<u>4/5</u>, you divide both by 4 and you get <u>4/5</u>

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3 years ago

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10. When Raphael solved the system below by using the method of elimination, he changed the second equationto -8x – 2y = -2. Wha

Alex17521 [72]

$\begin{gathered} 8x+3y=7\ldots eqn(1) \\ 4x+y=1\ldots.eqn(2) \end{gathered}$

The property that justifies multiplying through eqn(2) by -2 is;

the rationalization to align the coefficients of x in both equations with a view to eliminating the terms in x.

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1 year ago

Does anyone know this because clearly i dont

alina1380 [7]

I think it’s either A or C

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3 years ago

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Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago