Answer:
1) The net force is 5 N. The box is accelerating 10 m/s
2) The net force is 6.986 N. It is accelerating. Normal Force is 16.986
Explanation:
1) 20 N forward - 15 N backwards = a net force of 5 N
Acceleration: Acceleration = Net Force * Mass ( derived from Force = mass * acceleration).
a = 5 N / 2 kg
a= 2.5 m/s^2
2)
Answer:
The force exerted by the wood on the bullet is 399.01 N
Explanation:
Given;
mass of bullet, m = 0.0021 kg
initial velocity of the bullet, u = 497 m/s
final velocity of the bullet, v = 0
distance traveled by the bullet, S = 0.65 m
Determine the acceleration of the bullet which is the deceleration.
Apply kinematic equation;
V² = U² + 2aS
0 = 497² - (2 x 0.65)a
0 = 247009 - 1.3a
1.3a = 247009
a = 247009 / 1.3
a = 190006.92 m/s²
Finally, apply Newton's second law of motion to determine the force exerted by the wood on the bullet;
F = ma
F = 0.0021 x 190006.92
F = 399.01 N
Therefore, the force exerted by the wood on the bullet is 399.01 N
Condensation must occur. Water droplets collect on the cold surface when warm/humid air is in contact with it.
i just took this test and got it right.
I say that is D
because it makes sense
