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AleksandrR [38]
4 years ago
14

Materials that are magnetic have_________that are lined up in the same orientation?

Physics
1 answer:
Cerrena [4.2K]4 years ago
7 0
I say that is D
because it makes sense
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A hilly road is spiral in shape.​
Llana [10]
I- wym incorrect answer i-
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3 years ago
4. Provide an example of an isolated energy system and explain how it could be changed to create an open energy system. You may
GarryVolchara [31]
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Select the correct answer.
Ilia_Sergeevich [38]
Pretty sure it is B.
Because inertia is a tendency to do nothing or remain unchanged.
8 0
3 years ago
Heights of men on a baseball team have a​ bell-shaped distribution with a mean of 166 cm 166 cm and a standard deviation of 5 cm
kaheart [24]

Answer:

95 %

99.7 %

Explanation:

\mu = 166 cm = Mean

\sigma = 5 cm =  Standard deviation

a) 156 cm and 176 cm

166-5\times 2=156

166+5\times 2=176

From the empirical rule 95% of all values are within 2 standard deviation of the mean, so about 95% of men are between 156 cm and 176 cm.

b) 151 cm and 181 cm

166-5\times 3 =151

166+5\times 3=181

The empirical rule tells us that about 99.7% of all values are within 3 standard deviations of the mean, so about 99.7% of men are between 151 cm and 181 cm.

3 0
3 years ago
An infinite slab of charge of thickness 2z0 lies in the xy-plane between z=−z0 and z=+z0. The volume charge density rho(C/m3) is
Oksi-84 [34.3K]

Answer:

please read the answer below

Explanation:

To find the electric field you can consider the Gaussian law for a cylindrical surface inside the slab.

\int E dA=EA_{G}=\frac{Q_{int}}{\epsilon_o}

Q_{int}=\rho V_{G}

where Qint is the charge inside the Gaussian surface, AG is the area of the surface and rho is the charge density of the slab.

By using the formula for the volume of a cylinder you obtain:

V_{G}=\pi r^2h

where h is the height. If you assume that the slab is in the interval (-zo<z<z0) you can write VG:

V_{G}=\pi r^2 z

Finally, by replacing in the expression for E you get:

E=\frac{Q_{int}}{\epsilon_o A_G}=\frac{Q_{int}}{\epsilon_o \pi r^2}\frac{z}{z}=\frac{\rho z}{\epsilon_o}

E=\rho z/\epsilon_o

hence, for z>0 you obtain E=pz/eo > 0

for z<0 -> E=pz/eo < 0

7 0
3 years ago
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