Alright this to me seems to be the answer C if it’s not then that’s cuz I’m guessing
Answer:
6.30 M⁻¹s⁻¹.
Explanation:
As the reaction is first order with respect to a and b.
<em>The rate of the reaction = k [a][b],</em>
where, k is the rate constant of the reaction.
The rate of the reaction = 2.65 × 10⁻⁴ M/s,
[a] = 1.60 × 10⁻² M,
[b] = 2.67 × 10⁻³ M.
∴ k = (the rate of the reaction / [a][b]) = (2.65 × 10⁻⁴ M/s) / (1.60 × 10⁻² M)( 2.67 × 10⁻³ M) = 6.30 M⁻¹s⁻¹.
Answer:
Bromine
Explanation:
To identify the gas, you first need to find the moles of the gas. You can do this using the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Constant (0.08206 atm*L/mol *K)
-----> T = temperature (K)
After converting mL to L and Celsius to Kelvin, you can plug the values into the equation and simplify to find the moles.
P = 1.98 atm R = 0.08206 atm*L/mol *K
V = 752 mL / 1,000 = 0.752 L T = 62 °C + 273.15 = 335.15 K
n = ? moles
PV = nRT
(1.98 atm)(0.752 L) = n(0.08206 atm*L/mol *K)(335.15 K)
1.48896 = n(27.5024)
0.0541 = n
You can identify the gas by determining the molar mass of the gas, which is specific to each element. The molar mass exists as a ratio that compares the mass per 1 mole.
Molar Mass = mass / moles
Molar Mass = 4.32 g / 0.0541 moles
Molar Mass = 79.8 g/mol
This molar mass is closest to the molar mass of bromine (79.904 g/mol).
The most likely formula for an oxide formed between group 1a atom X and oxygen would be
X2O. - X is group 1a atom.
Please upload a photo of your question!
