Molar mass NaOH = 40.0 g/mol

Volume in liters of solution :

5 mL / 1000 => 0.005 L

number of moles :

4 / 40 => 0.1 moles

M = n / V

M = 0.1 / 0.005

= 20 mol/L or 20 M

hope this helps!

6 0

3 years ago

at what temperature in celsius would a gas have volume of 13.5 L at a pressure of 0.723 atm, if it had a volume of 17.8 L at a p

Alex

Answer:

initial temperature= $-3.31^{\circ}C$

Explanation:

Assuming that the given follows the ideal gas nature;

$P_1=0.723atm$

$V_1=13.5L$

$T_1=?$

$P_2=0.612atm$

$V_2=17.8L$

$T_2=28 ^{\circ}C =273+28K=301K$

mole of gass will remain same at any emperature:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

putting all the value we get:

$T_2 =269.7K =-3.31 ^{\circ} C$

initial temperature= $-3.31^{\circ}C$

6 0

3 years ago

How many moles of gas occupy 98 l at a pressure of 2.8 atmosphere and a temperature of 292

lara [203]

Answer:

n = 11.45 mol

Explanation:

Given data:

Number of moles = ?

Volume of gas = 98 L

Pressure = 2.8 atm

temperature = 292 K

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

2.8 atm × 98 L = n × 0.0821 atm.L/ mol.K × 292 K

274.4 atm.L = n × 23.97atm.L/ mol

n = 274.4 atm.L /23.97atm.L/ mol

n = 11.45 mol

8 0

3 years ago