Answer:
Percentage abundance of 121 Sb is = 57.2 %
Percentage abundance of 123 Sb is = 42.8 %
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.
For first isotope, 121 Sb :
% = x %
Mass = 120.9038 u
For second isotope, 123 Sb:
% = 100 - x
Mass = 122.9042 u
Given, Average Mass = 121.7601 u
Thus,
Solving for x, we get that:
x = 57.2 %
<u>Thus, percentage abundance of 121 Sb is = 57.2 %
</u>
<u>percentage abundance of 123 Sb is = 100 - 57.2 % = 42.8 %</u>
Answer is valence electron, they all have total of 2 valence electron.
remember group number = valence electron
Answer:
Option (3).
Explanation:
Transfer RNA or t RNA's is one of the type of the RNA molecule necessary for the synthesis of protein translation. This RNA works as a adaptor molecule and contains 70 to 90 nucleotide in length.
Transfer RNA contains an anti codon loop. This anti codon loop has the ability to recognize an mRNA codon and result in the formation of protein product.
Thus, the correct answer is option (3).
It would be known as a meth_(insert - ane, - ene, and -yne) hydrocarbon.
1 bond = -ane
2 bonds = - ene
And so on.
