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Karolina [17]
4 years ago
13

WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!

Chemistry
2 answers:
Andru [333]4 years ago
8 0

Answer:

A is the answer

Explanation:

Westkost [7]4 years ago
3 0

Hello!

I believe the answer is A) Anaphase.

I hope it helps!

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1. State how increasing the temperature of a gas changes its volume, assuming pressure is held
vredina [299]

Explanation:

the volume and temperature of a gas have a ditect relationship,as the temperature increases the volume also increases when pressure is held constand, heating the gas increases the kinetic energy of the particles or atoms,causing the gas to expand until the pressure returns to its original value

7 0
3 years ago
How does repeatability have an effect on scientific research?
Bas_tet [7]
In science it is best to continue research, and rinse and repeat. This allows for a stronger hypothesis if you're results are the same every time, or change your hypothesis if you stumble upon new results. <span />
5 0
3 years ago
Help me plssssssssssssssss
Sveta_85 [38]

Answer:

community according to me

7 0
2 years ago
Read 2 more answers
NEED HELP with 7. 8. 9. 10. 11. 12. And 14 !!
aleksley [76]

Answer:

1.      0.00040 calories

2.   8.57 calories

3.   0.196 calories

4.  68 calories

5. 243 calories

6.  83680 joules

7.  1,054,368 joules

8. 2.45 calories

9. 556 (it says calories to calories so it wouldn't change)

10. 28367.52 joules

11. 59.6 calories

12. 449.6 joules

13.  0.00234 calories

14. 23292.328 joules

15. 22877693.6 joules

Hope this helps!

Explanation:

6 0
3 years ago
A 76.0-gram piece of metal at 96.0 °C is placed in 120.0 g of water in a calorimeter at 24.5 °C. The final temperature in the ca
Phoenix [80]

The specific heat capacity of the metal given the data from the question is 0.66 J/gºC

<h3>Data obtained from the question</h3>
  • Mass of metal (M) = 76 g
  • Temperature of metal (T) = 96 °C
  • Mass of water (Mᵥᵥ) = 120 g
  • Temperature of water (Tᵥᵥ) = 24.5 °C
  • Equilibrium temperature (Tₑ) = 31 °C
  • Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
  • Specific heat capacity of metal (C) =?

<h3>How to determine the specific heat capacity of the metal</h3>

The specific heat capacity of the sample of the metal can be obtained as follow:

Heat loss = Heat gain

MC(M –Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

76 × C × (96 – 31) = 120 × 4.184 × (31 – 24.5)

C × 4940 = 3263.52

Divide both side by 4940

C = 3263.52 / 4940

C = 0.66 J/gºC

Learn more about heat transfer:

brainly.com/question/6363778

#SPJ1

6 0
2 years ago
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