Answer:
V = 12.93 L
Explanation:
Given data:
Number of moles = 0.785 mol
Pressure of balloon = 1.5 atm
Temperature = 301 K
Volume of balloon = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will put the values.
V = nRT/P
V = 0.785 mol × 0.0821 atm.L/ mol.K × 301 K / 1.5 atm
V = 19.4 L /1.5
V = 12.93 L
Answer:
Explanation:
Uma declaração verdade é identificada pelo de ela afirmar a verdade diferente das outras opções
Considering the Charles' law, the gas would have a temperature of -109.2 C.
<h3>Charles' law</h3>
Finally, Charles' law establishes the relationship between the volume and temperature of a gas sample at constant pressure. This law says that the volume is directly proportional to the temperature of the gas. That is, if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.
Charles' law is expressed mathematically as:

If you want to study two different states, an initial state 1 and a final state 2, the following is true:

<h3>Temperature of the gas in this case</h3>
In this case, you know:
- P1= 1800 psi
- V1= 10 L
- T1= 20 C= 293 K (being 0 C= 273 K)
- P2= 1800 psi
- V2= 6 L
- T2= ?
You can see that the pressure remains constant, so you can apply Charles's law.
Replacing in the Charles's law:

Solving:


<u><em>T2=163.8 K= -109.2 C</em></u>
The gas would have a temperature of -109.2 C.
Learn more about Charles's law:
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