Answer:
3.2N
Explanation:
Given parameters:
Mass of block = 1.5kg
Coefficient of kinetic friction = 0.6
Force of pull on block = 12N
Unknown:
Net force on the block = ?
Solution:
Frictional force is a force that opposes motion:
Net force = Force of pull - Frictional force
Frictional force = umg
u is coefficient of kinetic friction
m is the mass
g is the acceleration due to gravity
Frictional force = 0.6 x 1.5 x 9.8 = 8.8N
Net force = 12N - 8.8N = 3.2N
Answer:
About 6.26m/s
Explanation:
![mgh=\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=mgh%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
Divide both sides by mass:
![gh=\dfrac{1}{2}v^2](https://tex.z-dn.net/?f=gh%3D%5Cdfrac%7B1%7D%7B2%7Dv%5E2)
Since the point of equality of kinetic and potential energy will be halfway down the cliff, height will be 4/2=2 meters.
![(9.8)(2)=\dfrac{1}{2}v^2 \\\\v^2=39.4 \\\\v\approx 6.26m/s](https://tex.z-dn.net/?f=%289.8%29%282%29%3D%5Cdfrac%7B1%7D%7B2%7Dv%5E2%20%5C%5C%5C%5Cv%5E2%3D39.4%20%5C%5C%5C%5Cv%5Capprox%206.26m%2Fs)
Hope this helps!
Answer:
(C) 3.78 seconds
Explanation:
At the highest point, the velocity is equal to 0m/s
![v_{f}=v_{o}-gt](https://tex.z-dn.net/?f=v_%7Bf%7D%3Dv_%7Bo%7D-gt)
; t is the time to reach the highest point
The time the ball takes to return to its starting point after the ball reach its maximum height is the same:
![T_{descent}=t=\frac{v_{o}}{g}=\frac{37}{9.81}=3.78s](https://tex.z-dn.net/?f=T_%7Bdescent%7D%3Dt%3D%5Cfrac%7Bv_%7Bo%7D%7D%7Bg%7D%3D%5Cfrac%7B37%7D%7B9.81%7D%3D3.78s)
The amount of energy in food is measured in calories.
Wats and kilowatts are units for electricity. Grams are a unit of mass.
Well I believe the claim is if you use all its energy fr a long period of time it does so the claim is if the light is left on the battery runs out and flashlight stops working