1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
UNO [17]
2 years ago
7

Think back to the example in the Warm-Up: A business owner wants to open a restaurant, but many residents do not want a business

that is open late at night near their homes.
How are local governments structured to solve a local issue like this one?
Physics
1 answer:
Alexxandr [17]2 years ago
3 0

Answer:

In this case someone must file a petition to the local counsel and the counsel will hear both sides from the business owner and the public and then decide whether to release a business permit to the restaurant owner.

Explanation:

Hope this helps.

You might be interested in
How many milligrams are equivalent to 150 dekagrams?
dybincka [34]
 i believe  the answer is 1.5e+6

hope this helps!

4 0
3 years ago
Read 2 more answers
A uniform stick 1.5 m long with a total mass of 250 g is pivoted at its center. A 3.3-g bullet is shot through the stick midway
Andru [333]

Answer:

<em>63.44 rad/s</em>

<em></em>

Explanation:

mass of bullet = 3.3 g = 0.0033 kg

initial velocity of bullet v_{1} = 250 m/s

final velocity of bullet v_{2} = 140 m/s

loss of kinetic energy of the bullet = \frac{1}{2}m(v^{2} _{1} - v^{2} _{2})

==> \frac{1}{2}*0.0033*(250^{2}  - 140^{2} ) = 70.785 J

this energy is given to the stick

The stick has mass = 250 g =0.25 kg

its kinetic energy = 70.785 J

from

KE = \frac{1}{2} mv^{2}

70.785 = \frac{1}{2}*0.25*v^{2}

566.28 = v^{2}

v= \sqrt{566.28} = 23.79 m/s

the stick is 1.5 m long

this energy is impacted midway between the pivot and one end of the stick, which leaves it with a radius of 1.5/4 = 0.375 m

The angular speed will be

Ω = v/r = 23.79/0.375 =<em> 63.44 rad/s</em>

5 0
2 years ago
n ultraviolet light beam having a wavelength of 130 nm is incident on a molybdenum surface with a work function of 4.2 eV. How f
pashok25 [27]

Answer:

The speed of the electron is 1.371 x 10⁶ m/s.

Explanation:

Given;

wavelength of the ultraviolet light beam, λ = 130 nm = 130 x 10⁻⁹ m

the work function of the molybdenum surface, W₀ = 4.2 eV = 6.728 x 10⁻¹⁹ J

The energy of the incident light is given by;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

f = c / λ

E = \frac{hc}{\lambda} \\\\E = \frac{6.626*10^{-34} *3*10^{8}}{130*10^{-9}} \\\\E = 15.291*10^{-19} \ J

Photo electric effect equation is given by;

E = W₀ + K.E

Where;

K.E is the kinetic energy of the emitted electron

K.E = E - W₀

K.E = 15.291 x 10⁻¹⁹ J - 6.728 x 10⁻¹⁹ J

K.E = 8.563 x 10⁻¹⁹ J

Kinetic energy of the emitted electron is given by;

K.E = ¹/₂mv²

where;

m is mass of the electron = 9.11 x 10⁻³¹ kg

v is the speed of the electron

v = \sqrt{\frac{2K.E}{m} } \\\\v =  \sqrt{\frac{2*8.563*10^{-19}}{9.11*10^{-31}}}\\\\v = 1.371 *10^{6} \ m/s

Therefore, the speed of the electron is 1.371 x 10⁶ m/s.

8 0
3 years ago
The Olympic record for a marathon is 2.00 hour 9.00 minute 21.0 seconds if the average speed of the runner achieving this record
iren2701 [21]
(2.00 hours) x (3,600 seconds/hour)  =  7,200 seconds

(9.00 minutes) x (60 seconds/minute)  =  540 seconds

The record time = (7,200 + 540 + 21) = 7,761 seconds

Distance  =  (speed) x (time)

                 = (5.436 m/s) x (7,761 sec)  =<span>  42,188.8 meters
________________________________________________
</span>
The official length of the marathon run is  42,195 meters.
If we divide that by the record time in the question, we get

                       5.4368... m/s .

Rounded to the nearest thousandth, that's  5.437 m/s.

If the question had given the speed as  5.437  instead of  5.436 ,
then we would have calculated the distance to be 

            (5.437 m/s) x (7,761 sec)  =<span>  42,196.6 meters,

4.6 meters closer to the official distance than the answer we did get.
</span>
3 0
2 years ago
If s is the specific heat capacity of 4kg water, what is the specific heat capacity of 16kg
uranmaximum [27]

Answer: d

Explanation: divide it by 4

6 0
2 years ago
Other questions:
  • What physical characteristic is the same for a particular substance regardless of the sample size .
    12·1 answer
  • What is the kinetic energy of an automobile with a mass of 1252 kg traveling at a speed of 12 m/s?
    14·1 answer
  • Which of the following best describes a plane?
    14·1 answer
  • In t-ball, young players use a bat to hit a stationary ball off a stand. The 140 g ball has about the same mass as a baseball, b
    10·1 answer
  • How many nanoseconds does it take light to travel 3.50 ft in vacuum?
    14·1 answer
  • What is required for equilibrium to exist
    5·1 answer
  • A parallel plate capacitor is connected to a battery that maintains a constant potential difference between the plates. If the p
    6·1 answer
  • An advertisement for a new fish food claims that lab studies show that fish grew three inches in three weeks while eating the fo
    8·1 answer
  • Sentences about energy giving food?​
    9·1 answer
  • The process of losing heat that does not
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!