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3 years ago

A plane flying against a jet stream will travel faster than a plane traveling with a jet stream.

2 answers:

7 0

Their "airspeeds" (speed through the air) are equal, but the one traveling in the
same direction as the jet-stream appears to move along the ground faster.

koban [17]3 years ago

3 0

<h2><u><em>FALSE, THE PLANE HAS MORE RESISTANCE THAN THE PLANE TRAVELING WITH THE JET STREAM</em></u></h2>

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Two identical loudspeakers are driven in phase by the same amplifier. The speakers are positioned a distance of 3.2 m apart. A p

arsen [322]

Answer:

C) 413 Hz

Explanation:

For destructive interference, the path difference ΔL = (n + 1/2)λ where ΔL = L₂ - L₁ where L₁ = person's distance from one speaker (the closer one) = 5.0m and L₂ = person's distance from other speaker (the farther one) = 6.2 m and λ = wavelength = v/f where v = speed of sound = 330 m/s and f = frequency

So, ΔL = (n + 1/2)λ

L₂ - L₁ = (n + 1/2)v/f

f = (n + 1/2)v/(L₂ - L₁)

At the second lowest frequency that results in destructive interference at the point where the person is standing, n = 1.

So,

f = (1 + 1/2)v/(L₂ - L₁)

f = 3v/2(L₂ - L₁)

Substituting the values of the variables into the equation, we have

f = 3v/2(L₂ - L₁)

f = 3(330 m/s)/2(6.2 m - 5.0 m)

f = 3(330 m/s)/2(1.2 m)

f = 990 m/s ÷ 2.4 m)

f = 412.5 Hz

f ≅ 413 Hz

5 0

3 years ago

Can a 12 inch rubber band fit a 22 pound rubber band ball

Vlada [557]

Answer:

if it is a thiner one, yes it will fit because they can expand a pretty far distance

Explanation:

4 0

3 years ago

What is the shape of the orbit of satellites?

Rainbow [258]

All objects in orbit must follow the path of an ellipse (one of Keplers laws)

8 0

4 years ago

An object is moving with an initial velocity of 19 m/s.It is then subject to a constant acceleration of 2.5 m/s for 15s.How far

bija089 [108]

Answer:

566.3 m

Explanation:

The distance travelled by the object can be found by using the SUVAT equation:

$d=ut+\frac{1}{2}at^2$

where

u is the initial velocity

t is the time

a is the acceleration

For the object in this problem:

u = 19 m/s

a = 2.5 m/s^2

Substituting t = 15 s, we find the distance travelled:

$d=(19)(15)+\frac{1}{2}(2.5)(15)^2=566.3 m$

7 0

4 years ago

Bats can detect small objects such as insects that are of a size on the order of a wavelength. if bats emit a chirp at a frequen

crimeas [40]

The smallest size of the insect that the bats can detect corresponds to the wavelength of the chirp they emit.

Their chirp has a frequency of
$f=69.3 kHz=69.3 \cdot 10^3 Hz$
and the speed of the chirp is equal to the speed of sound in air:
$v=330 m/s$
Therefore the wavelength of the chirp is
$\lambda= \frac{v}{f}= \frac{330 m/s}{69.3 \cdot 10^3 Hz}=4.76 \cdot 10^{-3} m$
which corresponds to a size of 4.76 mm.

6 0

4 years ago