Answer:
Explanation:
The rod will act as pendulum for small oscillation .
Time period of oscillation
angular frequency ω = 2π / T
= 
b )
ω = 20( given )
velocity = ω r = ω l
Let the maximum angular displacement in terms of degree be θ .
1/2 m v ² = mgl ( 1 - cosθ ) ,
[ l-lcosθ is loss of height . we have applied law of conservation of mechanical energy .]
.5 ( ω l )² = gl( 1 - cos θ )
.5 ω² l = g ( 1 - cosθ )
1 - cosθ = .5 ω² l /g
cosθ = 1 - .5 ω² l /g
θ can be calculated , if value of l is given .
Answer:
Find a stick sutible enough (and strong).
add a fishing string or a strong piese of plastic string that will hold
put on a hook or use a paper pin and bend it into a hook
attach hook to string and put a small stick on or anything that will float on the water to act as a bobber
Explanation:
Answer:
V = L A = L pi R^2 volume of wire
V = 50 cm * .01 cm^2 = .5 cm^3
d(density) = 3.5 gm / .5 cm^3 = 7.0 gm/cm^3
A micrometer caliper could measure the diameter of the wire.
The velocity of the ball at its maximum height is zero (0).
The given parameters;
- <em>initial vertical velocity of the ball, </em>
<em> = 18.5 m/s</em> - <em>height of the cliff, h = 25</em>
<em />
In a projectile motion, as the object ascends upwards, its vertical velocity decreases and eventually becomes zero as the object reaches maximum height.
This <em>velocity</em> starts to increase again as the object descends downwards and finally becomes maximum before the object hits the ground.
Thus, we can conclude that the velocity of the ball at its maximum height is zero (0).
Learn more here:brainly.com/question/10693605
