A copper wire of diameter 3.256mm carries a current of 6.25mA. the potential difference is mathematically given as
V=2.0657*10^{-4}
<h3>What is the potential difference across a 200m length of the wire?</h3>
Generally, the equation for is mathematically given as
R=Pl/A
Therefore
R=1.72*10^{-8}*2.00/\pi*(1.628)^2*10^{-6}
R=1.652*10^{-2}
In conclusion,
V=IR
V=12.5*10^{-3}*1.652*10^{-2}
V=2.0657*10^{-4}
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Answer:
Impulse = 50,000 J
Explanation:
Given: force = 100,000 kg ms^2 or N; time = 0.5 s
Unknown: impulse = ?
Equation: impulse = (force)(time)
Substitute: impulse = (100,000 kg ms^2 or N)(0.5 s)
Solution: impusle = 50,000 kg ms^2 or J
N= energy efficiency pout means output and pin means input the reason this would show efficiency is because your output should be greater then your input and because depending on how small your number is after your division will tell you how efficient it is you want a big number.
Answer:
0.367A = Current of both resistors
For resistor 1: 1.89W; For resistor 2: 11.3W
Explanation:
When the resistors are connected in series, the equivalent resistance is the sum of both resistors, that is:
R = 14.0Ω + 84.0Ω = 98.0Ω
Using Ohm's law, we can find the current of the circuit (Is the same for both resistors):
V = RI
V / R = I
36.0V / 98.0Ω = I
<h3>0.367A = Current of both resistors</h3><h3 />
Power is defined as:
P = I²*R
For resistor 1:
P = 0.367A²*14.0Ω = 1.89W
For resistor 1:
P = 0.367A²*84.0Ω = 11.3W