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slamgirl [31]
3 years ago
8

What is the voltage output (in V) of a transformer used for rechargeable flashlight batteries, if its primary has 480 turns, its

secondary 8 turns, and the input voltage is 118 V
Physics
1 answer:
Lera25 [3.4K]3 years ago
3 0

Answer:

1.97 V

Explanation:

Applying

N1/N2 = V1/V2................... Equation 1

Where N1 = primary turns, N2 = Secondary turns, V1 = primary/input voltage, V2 = secondary/output voltage.

make V2 the subject of the equation

V2 = V1(N2/N1)............. Equation 2

Given: V1 = 118 V, N1 = 480 turns, V2 = 8 turns.

Substitute into equation 2

V2 = 118(8/480)

V2 = 1.97 V.

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What is the output voltage from a step up transformer with 25 turns in the primary coil and 75 turns in the secondary coil if th
Greeley [361]

Answer:

360 V

Explanation:

We can use the transformer equation:

\frac{V_p}{N_p}=\frac{V_s}{N_s}

where

V_p is the primary (input) voltage

N_p is the number of turns in the primary coil

V_s is the secondary (output) voltage

N_s is the number of turns in the secondary coil

In this problem,

V_p = 120 V\\N_p = 25\\N_s = 75

Substituting into the equation, we can find the output voltage:

V_s = N_s \frac{V_p}{N_p}=(75)\frac{120}{25}=360 V

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A block of aluminum at a temperature of T1 = 32 degrees C has a mass of m1 = 12 kg. It is brought into contact with another bloc
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Answer:T=21.33 ^{\circ}

Explanation:

Given

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