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Dmitriy789 [7]
2 years ago
14

Find the area of the shaded region

Mathematics
2 answers:
Alika [10]2 years ago
4 0
It’s b and if you need to show your work tell me
ruslelena [56]2 years ago
4 0
The correct answer is B
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What is theoretical vs practical domain in an exponential equation. Plz provide an example too
olya-2409 [2.1K]

Answer:

The theoretical probability of an event occurring is an "expected" probability based upon knowledge of the situation. It is the number of favorable outcomes to the number of possible outcomes. Example: ... There are 6 possible outcomes when rolling a die: 1, 2, 3, 4, 5, and 6. The only favorable outcome is rolling a 6.Practical domains and ranges narrow the solution sets to be realistic within defined parameters.The possible values of "x" is called the domain. The possible values of "y" is called the range.

Step-by-step explanation:

7 0
3 years ago
The 12th term of the arithmetic sequence is 10.5. The 18th term of this sequence is 13.5. Find the common difference and the fir
xxMikexx [17]

Answer:

common difference is 0.5

first term is 5

Step-by-step explanation:

<em>use </em><em>the </em><em>formula</em><em> for</em><em> </em><em>the</em><em> </em><em>nth </em><em>term </em><em>of </em><em>an </em><em>ap </em><em>Tn=</em><em>a+</em><em>(</em><em>n-1)</em><em>d</em>

<em>T12=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>T18=</em><em>1</em><em>3</em><em>.</em><em>5</em>

<em>therefore</em><em> </em><em>come </em><em>up </em><em>with </em><em>two </em><em>equations</em>

<em>T12=</em><em>a+</em><em>(</em><em>1</em><em>2</em><em>-</em><em>1</em><em>)</em><em>d</em>

<em>1</em><em>0</em><em>.</em><em>5</em><em>=</em><em>a+</em><em>1</em><em>1</em><em>d</em><em>(</em><em>1</em><em>s</em><em>t</em><em> </em><em>equation</em><em>)</em>

<em>T18</em><em>=</em><em>a+</em><em>(</em><em>1</em><em>8</em><em>-</em><em>1</em><em>)</em><em>d</em>

<em>1</em><em>3</em><em>.</em><em>5</em><em>=</em><em>a+</em><em>1</em><em>7</em><em>d</em><em>(</em><em>2</em><em>n</em><em>d</em><em> </em><em>equation</em><em>)</em>

<em>then </em><em>solve </em><em>both </em><em>as </em><em>a </em><em>simultaneous</em><em> </em><em>equation</em>

<em>a+</em><em>1</em><em>1</em><em>d</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a+</em><em>1</em><em>7</em><em>d</em><em>=</em><em>1</em><em>3</em><em>.</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em>-6d/</em><em>-</em><em>6</em><em>=</em><em>-</em><em>3</em><em>/</em><em>-</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d=</em><em>0</em><em>.</em><em>5</em>

<em>use </em><em>one </em><em>of</em><em> the</em><em> </em><em>equations</em><em> </em><em>to </em><em>find </em><em>the </em><em>first</em><em> </em><em>term</em>

<em>a+</em><em>1</em><em>1</em><em>(</em><em>0</em><em>.</em><em>5</em><em>)</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a+</em><em>5</em><em>.</em><em>5</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>-</em><em>5</em><em>.</em><em>5</em>

<em>a=</em><em>5</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

<em>please </em><em>mark</em><em> </em><em>as </em><em>brainliest</em>

7 0
3 years ago
I’ll give brainliest IF ITS AN ACRUAL ANSWER, ALL USELESS ONES WILL BE REPORTED
Llana [10]

Answer:

C

Step-by-step explanation:

pls mark brainliest

multiply the numerator and denominator by the same number so, that all the fractions have a denominator of 12.

4 0
3 years ago
Read 2 more answers
Solve the inequality for V.<br><br> -8.3 _&gt;_ V - 1.9
Arada [10]
First keep in mind that the given value is negative and that it is greater than or equal to whatever '<em>v</em>' is.

-8.3  \geq v - 1.9

When solving for a variable in any equation, you do something to both sides in order to keep it equal. Here, <em>v</em> is being subtracted by 1.9; therefore we can add 1.9 to both sides in order to isolate <em />the variable.

-8.3 + 1.9  \geq v - 1.9 + 1.9
-6.4 \geq v

Despite not needing a value for the question, it is worth noting that since this is an inequality, <em>v </em>can be any value from -6.4 to ∞ in order to make it true.
6 0
2 years ago
Write the product in standard form.<br>(2 - 3i)(2 + i)​
Stels [109]

Answer:

Brainelist?

Step-by-step explanation:

7-4i

just use a online calculator

8 0
3 years ago
Read 2 more answers
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