Answer:
The rate of change of the height is - 4 ft/s
Solution:
As per the question:
Height of the person, y = 5 ft
The rate at which the person walks away,
Distance of the spotlight from the wall, x = 40 ft
Now,
To calculate the rate of change in the height, of the person when, x = 10 m:
From fig 1.
xy = 200 (1)
Differentiating the above eqn w.r.t time t:
Thus
(2)
From eqn (1):
When x = 10 ft
10y = 200
y = 20 ft
Using eqn (2):
Color rarely determines a mineral type.
Answer:
3.44 metres
Explanation:
To determine the vector sum of the displacements Δd1 = 2.4 m [32° S of W]; Δd2 = 1.6 m [S]; and Δd3 = 4.9 m [27° S of E], resolve the given parameters into x - component and y - component.
Resolving into x - component
- 2.4cos32 + 4.9cos27 = 2.3306
Resolving into y - component
- 2.4sin32 - 4.9sin27 - 1.6 = - 2.553
The vector sum of the displacement will be
Sqrt( 2.3^2 + 2.6^2) =
Sqrt ( 11.81)
3.44 m
Therefore, the vector sum of the displacements is 3.44 metres
Answer:
Presiune = 350 N/m²
Explanation:
Având în vedere următoarele date;
Forța = 700 N
Suprafață = 2 m²
Pentru a găsi presiunea;
Matematic, presiunea este dată de formulă;
Presiune = forță/zonă
Înlocuind în formulă, avem;
Presiune = 700/2
Presiune = 350 N/m²