Question

Find the value of T1 if 1 = 30°, 2 = 60°, and the weight of the object is 139.3 newtons.

Answer 1

Answer:

Option A (69.56 newtons) is the appropriate solution.

Explanation:

According to the question,

On the X-axis,

⇒ $T_1Cos30^{\circ}-T_2Cos60^{\circ}=0$

or,

    $T_1Cos 30^{\circ}=T_2Cos60^{\circ}$

On substituting the values, we get

      $T_1\times \frac{\sqrt{3} }{2}=T_2\times \frac{1}{2}$

      $T_1\times \sqrt{3} =T_2$....(equation 1)

On the Y-axis,

⇒ $T_1Sin30^{\circ}+T_2Sin60^{\circ}=139.3 \ N$

                        $\frac{T_1}{2} +\frac{\sqrt{3} }{2} =139.2 \ N$

                    $T_1+\sqrt{3}T_2=139.2\times 2$

From equation 1, we get

           $T_1+\sqrt{3}\times \sqrt{3}T_1 =278.4 \ N$

                        $T_1+3T_1=278.4 \ N$

                                $4T_1=278.4 \ N$

                                  $T_1=\frac{278.4}{4}$

                                       $=69.6 \ N$