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SCORPION-xisa [38]
3 years ago
8

A sprinter who is running a 200-m race travels the second 100 m in much less time than the first 100m because

Physics
2 answers:
chubhunter [2.5K]3 years ago
4 0

Answer:

The sprinter must overcome inertia and accelerate during the first 100 m.

Harrizon [31]3 years ago
3 0

Answer:

He is warmed up now

Explanation:

His muscles are better and stretched now

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How can you safely experiment with plants during a scientific investigation?
liubo4ka [24]

I would think the answer is c.

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A rose plant inherited two alleles for white flower petals.
Alik [6]

Answer:

a

Explanation:

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The number of mushrooms needed by a pizza restaurant is given by the
kupik [55]

Answer: 24

Explanation:

Given the following equation:

g=3n

Where g is the number of mushrooms in a pizza and n the number of pizzas.

If we know the restaurant will make 8 pizzas (n=8), then:

g=3(8)

g=24 This is the needed number of mushrooms for 8 pizzas

8 0
3 years ago
When is the velocity of a mass on a spring at its maximum value?
ehidna [41]

Answer:

A.  when the mass has a displacement of zero

Explanation:

The velocity of a mass on a spring can be calculated by using the law of conservation of energy. In fact, the total energy of the mass-spring system is equal to the sum of the elastic potential energy (U) of the spring and the kinetic energy (K) of the mass:

E=U+K=\frac{1}{2}kx^2 + \frac{1}{2}mv^2

where

k is the spring constant

x is the displacement of the mass with respect to the equilibrium position of the spring

m is the mass

v is the velocity of the mass

Since the total energy E must remain constant, we can notice the following:

- When the displacement is zero (x=0), the velocity must be maximum, because U=0 so K is maximum

- When the displacement is maximum, the velocity must be minimum (zero), because U is maximum and K=0

Based on these observations, we can conclude that the velocity of the mass is at its maximum value when the displacement is zero, so the correct option is A.


8 0
3 years ago
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With an initial velocity of 20km per hour a car accelerated at 8m/s2 for 10s,what is the position of the car at the end of 10s
Dima020 [189]
  • initial velocity=u=20km/h=5.5m/s
  • Acceleration=a=8m/s^2
  • Time=t=10s

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto s=5.5(10)+\dfrac{1}{2}(8)(5.5)^2

\\ \sf\longmapsto s=55+4(5.5)^2

\\ \sf\longmapsto s=55+4(30.25)

\\ \sf\longmapsto s=55+121

\\ \sf\longmapsto s=176m

4 0
2 years ago
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