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2 years ago

PLEASE HELP ME! WILL MARK BRAINlIEST!!

Mathematics

1 answer:

vivado [14]2 years ago

6 0

Answer:

1.) Increase

2.) Decrease

3.) Increase

4.) Decrease

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The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .

Equate the right-hand side of these two equations:

$0.810\, x \approx 0.649\, (x + 20)$ .

Solve for $x$ :

$x \approx 81\; \rm ft$ .

Hence, the height of the top of this tree relative to the base of the hill would be $(x + 20)\; {\rm ft}\approx 101\; \rm ft$ .

6 0

3 years ago

There are 12 people in a class. 10 are randomly chosen. How many possible combinations are there?

Mazyrski [523]

long way

12 x 11 x 10 x 9 x 8 x 7 x6 x5 x4 x3x2/ 10x9x8x7x6x5x4x3x2x

but you can shorten that by crossing out identical numbers so you get 12 x 11

12 x 11 = 132 combinations

3 0

3 years ago

Write a function to represent the set of ordered pairs.<br> {(2, 2), (3,7). (4, 14), (5,23)}

MrMuchimi

Answer:

Step-by-step explanation:

The set of ordered pairs {(1 , 7) , (−1 , 7) , (8 , −6) , (−3 , 2)} is a function

The set of ordered pairs {(4 , 7) , (−1 , 2) , (4 , −6) , (−3 , −2)} is not a

function

The set of ordered pairs {(3 , 7) , (−1 , 2) , (−4 , −2) , (−3 , −2)} is a function

The set of ordered pairs {(−3 , 7) , (1 , 2) , (4 ,−2) , (12,−4)} is a function

An ordered pair represents a relationship between two values

The first value is the input the second value is the output

1. A relation is a set of inputs and outputs

2. A function is a relation with one output for each input

3. All functions are relations

{(1 , 7) , (−1 , 7) , (8 , −6) , (−3 , 2)}

∵ Each x-coordinate in each ordered pair has only one y-coordinate

∴ The relation above is a function

The set of ordered pairs {(1 , 7) , (−1 , 7) , (8 , −6) , (−3 , 2)} is a function

{(4 , 7) , (−1 , 2) , (4 , −6) , (−3 , −2)}

∵ The x-coordinate 4 has two values of y (7 and -6)

∴ The relation above is not a function

The set of ordered pairs {(4 , 7) , (−1 , 2) , (4 , −6) , (−3 , −2)} is not a

function

{(3 , 7) , (−1 , 2) , (−4 , −2) , (−3 , −2)}

∵ Each x-coordinate in each ordered pair has only one y-coordinate

∴ The relation above is a function

The set of ordered pairs {(3 , 7) , (−1 , 2) , (−4 , −2) , (−3 , −2)} is a function

{(−3 , 7) , (1 , 2) , (4 ,−2) , (12,−4)}

∵ Each x-coordinate in each ordered pair has only one y-coordinate

∴ The relation above is a function

The set of ordered pairs {(−3 , 7) , (1 , 2) , (4 ,−2) , (12,−4)} is a function

6 0

3 years ago

4,000000 has more whole number places than 40,000

jonny [76]

You have divided 4,000000 by 100 so it became 40000 so 4000000 has 100 more whole number places

3 0

3 years ago

How do measurements of time differ for events in a frame of reference that moves at 50% of the speed of light relative to us? At

ZanzabumX [31]

Answer with explanation:

Relation between Speed , Distance and time

Distance =Speed × Time

→It means Speed is inversely Proportional to time.

As distance will remain constant , in that frame of reference

If speed of light in a Medium

$=s=3 \times 10^8 \frac{\text{meter}}{\text{second}}$

Then, time taken to cross the medium = t seconds or hours or another unit of time.

Now, If speed of light is 50% of the speed of light relative to us

That is Speed of light in another medium

$=w=\frac{50}{100} \times 3 \times 10^8\\\\=1.5 \times 10^8 \frac{\text{meter}}{\text{second}}$

Then, time taken to cross the medium = 2t seconds or hours or another unit of time.

Using Unitary Method

$\rightarrow v_{1}\times t_{1}=v_{2} \times t_{2}\\\\1.\rightarrow 3 \times 10^8 \times t=\frac{50}{100} \times 3 \times 10^8 \times t_{1}\\\\t_{1}=2t\\\\2.\rightarrow 3 \times 10^8 \times t=\frac{99.5}{100} \times 3 \times 10^8 \times t_{2}\\\\t_{2}=\frac{1000t}{995}\\\\t_{2}=\frac{200t}{199}$

7 0

3 years ago

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