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3 years ago

What is the correct description for the graph of the inequality, y < 42 – 3?

Mathematics

1 answer:

Varvara68 [4.7K]3 years ago

8 0

Answer: The graph is a solid line. The test point (0,0) does not satisfy the inequality.

Explanation:
The line is solid because it is less than or EQUAL TO. The test point does not satisfy because if you replace y and x with 0, it will not be true. 0 is not less than or equal to -3, therefore (0,0) does not satisfy the inequality.

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A band has 36 members. They are arranged into 6 equal rows. How many band members are in each row? Can the same 36 members be pl

Galina-37 [17]

Answer:

6 people would be in each row // It isn't possible for there to be 7 equal rows

Step-by-step explanation:

36 members/6 rows= 6 people per row // 36 members/7 rows= 5.14..... people per row (just doesn't work!)

6 0

3 years ago

Can some one do all these questions for me.

Zielflug [23.3K]

Which questions can you please send a link? :)

6 0

3 years ago

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Elan Coil [88]

The area of a circle is pi • radius^2

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3 years ago

1) 1, 4, 16, 64, ... CR=L Next 3 Terms:

avanturin [10]

Answer:

256, 1024, 4096.

Step-by-step explanation:

The rule is x*4.

--> 1*4 = 4.

--> 4*4 = 16.

--> 16*4 = 64.

--> 64*4 = 256.

--> 256*4 = 1024.

--> 1024*4 = 4096.

4 0

3 years ago

Read 2 more answers

Find cos(2*ABC) 100POINTS

juin [17]

Answer:

$-\dfrac{7}{25}$

Step-by-step explanation:

Trigonometric Identities

$\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B$

Trigonometric ratios

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos(\angle ABC)=\dfrac{3}{5}$

$\sin(\angle ABC)=\dfrac{4}{5}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}$

7 0

2 years ago

Read 2 more answers