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Tems11 [23]
3 years ago
7

Telepone wires sag in summer.Why​

Physics
1 answer:
BartSMP [9]3 years ago
6 0
The telephone wires will sag in summer due to expansions. While putting up the wires between the pole care is taken care in winter they are kept light so that they may not sag too much. ... So telephone wires will sag in summer due to expansion while you do suspect because of because of because of sighing expansion.
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Why is the answer A and not C?<br>please help!​
MariettaO [177]

Answer:

because it gives a complete thought

4 0
3 years ago
If the distance between two asteroids is halved, the gravitational force they exert on each other will
mamaluj [8]

Answer:

e) Be four times greater

Explanation:

Here we have to use Newton's gravitational law that relates the gravitational force between two objects with their masses (m_{1} & m_{2}) and the distance between them (r) in the next way:

F=G\frac{m_{1}m_{2}}{r^{2}} (2)

Now if distance between asteroids is halved:

F_{2}=G\frac{m_{1}m_{2}}{(\frac{r}{2})^{2}}

F_{2}=G\frac{m_{1}m_{2}}{\frac{r^{2}}{4}}

F_{2}=G\frac{4m_{1}m_{2}}{r^{2}}=4G\frac{m_{1}m_{2}}{r^{2}}

Note that G\frac{m_{1}m_{2}}{r^{2}} because (1) is F so:

F_{2}=4F

It's four times greater!

3 0
3 years ago
Suppose your friend investigated the color of pea pods and concluded that green pods (G) were dominant over yellow pods (g).
Katarina [22]

Answer:

Terms in this set (25) Mendel crossed true-breeding plants having yellow peas with plants having green peas. The resulting plant had all yellow peas. An F1 cross resulted in 3/4ths of the plants having yellow peas and 1/4th of the plants having green peas.

Explanation:

5 0
3 years ago
The sound from a loud speaker has an intensity level of 80 db at a distance of 2.0m. Consider the speaker to be a point source,
Tamiku [17]

Answer:

2.83m

Explanation:

The information that we have is

Intensity at 2.0 m: I=80dB and r_{1}=2m

we need an intensity level of: I_{2}=40dB

thus, we are looking for the distance r_{2}.

which we can find with the law for intensity and distance:

(\frac{r_{2}}{r_{1}} )^2=\frac{I_{1}}{I_{2}}

we solve for r_{2}:

\frac{r_{2}}{r_{1}}=\sqrt{\frac{I_{1}}{I_{2}} }\\\\r_{2}=r_{1}\sqrt{\frac{I_{1}}{I_{2}} }

and we substitute the known values:

r_{2}=(2m)\sqrt{\frac{80dB}{40dB} }\\\\r_{2}=(2m)\sqrt{2}\\ r_{2}=2.83m

at a distance of 2.83m the intensity level is 40dB

5 0
3 years ago
After the ball reaches the top and begins its return back down, by how much does it speed increase each second?
FrozenT [24]

After the ball reaches the top and begins its return back down, it's just a falling object that's been dropped.  

The amount that its downward speed increases every second is just the acceleration of gravity on Earth.

That's <em>9.81 meters per second</em> every second.

7 0
4 years ago
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