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Umnica [9.8K]
3 years ago
10

At some point, not close to its ends, within a solenoid of arbitrary length, calculate the approximate magnetic field if the sol

enoid carries a current 10.0 A and has 110.0 turns per meter of the solenoid's length.

Physics
1 answer:
GarryVolchara [31]3 years ago
5 0

Answer: The approximate magnetic field is 1.38 × 10^-3T

Explanation: Please see the attachment below

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How do you add scientific notation if the problem is like this:<br>3.72 x 10^9  +  5.46 x 10^8?
Crazy boy [7]
You can only add or subtract numbers in scientific notation if they have
the same power of 10.  If they're different, then you have to change one
to match the other one.

Here are both ways to do your example:

3.72x 10^9 = 37.2x10^8

(37.2 x 10^8)+(5.46 x 10^8) = (37.2+5.46) x 10^8 = 42.66x10^8 = <em>4.266x10^9</em>

=======================

5.46 x 10^8 = 0.546 x 10^9

3.72 x 10^9 + 0.546 x 10^9 = (3.72 + 0.546) x 10^9 = <em>4.266 x 10^9</em>
3 0
4 years ago
Use the drop-down menus to complete the statement.
lbvjy [14]

Answer:

kinetic and electrical

Explanation:

answered on edu

6 0
3 years ago
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Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equatio
yarga [219]

Answer:

m(P4) =  46.175 (grams)

m (KClO3) = 149 (grams)


Explanation:

1) n(P4) = n(P4O10);

m(P4)/M(P4) = m(P4O10)/M(P4O10);

m(P4) = M(P4)*m(P4O10)/M(P4O10)
          = 123.90*105.8/283.89
          = 46.175 (grams)

2) Analogously, 10n(P4O10) = 3n(KClO3)

m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
                = 10*122.55*105.8/283.89/3
                = 149 (grams).

6 0
2 years ago
What is the kinetic energy in Joules of a 1,500kg car traveling at 75mph?What is the kinetic energy in Joules of a 1,500kg car t
Sergio039 [100]

Answer: 2812500 joules

Explanation:

Mass of car = 1500kg

Velocity of car = 75mph

Kinetic energy = ?

Recall that kinetic energy is the energy possessed by a moving object, and it depends on its mass M and velocity, V

Thus, Kinetic energy = 1/2 x mv^2

= 1/2 x 1000kg x (75mph)^2

= 0.5 x 1000kg x (75mph)^2

= 500 x 5625

= 2812500 joules

Thus, the car travels with a kinetic energy of 2812500 joules

5 0
3 years ago
500km is equal to how many millimeters
Sindrei [870]

Answer:

500000000

if you can give me brainliest that would be great

7 0
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