A. How much work is being done to hold the beam in place?
Work is the product of Force and Displacement. Since there
is no Displacement involved in just holding the beam in place, hence the work
is zero.
B. How much work was done to lift the beam?
In this case, force is simply equal to weight or mass
times gravity. Hence the work is:
Work = weight * displacement
Work = 500 lbf * 100 ft
Work = 50,000 lbf * ft
C. How much work would it take if the steel beam were
raised from 100 ft to 200ft?
The displacement is still 100 ft since 200 – 100 = 100 ft,
hence the work done is still similar in B which is:
<span>Work = 50,000 lbf * ft</span>
The answer to your question will be C. because they are very inexpensive and are readily available but they will eventually deplete because we use them faster than they can be produced we use what has been building up.
False. Velocity is a vector and is measured in m/s (in SI, anyway).
Answer:
e. The torque is the same for all cases.
Explanation:
The formula for torque is:
τ = Fr
where,
τ = Torque
F = Force = Weight (in this case) = mg
r = perpendicular distance between force an axis of rotation
Therefore,
τ = mgr
a)
Here,
m = 200 kg
r = 2.5 m
Therefore,
τ = (200 kg)(9.8 m/s²)(2.5 m)
<u>τ = 4900 N.m</u>
<u></u>
b)
Here,
m = 20 kg
r = 25 m
Therefore,
τ = (20 kg)(9.8 m/s²)(25 m)
<u>τ = 4900 N.m</u>
<u></u>
c)
Here,
m = 8 kg
r = 62.5 m
Therefore,
τ = (8 kg)(9.8 m/s²)(62.5 m)
<u>τ = 4900 N.m</u>
<u></u>
Hence, the correct answer will be:
<u>e. The torque is the same for all cases.</u>
What’s Brainlyest? Can you post a picture of the question or farther explain what (m>s) means?
