<h2><u><em>Well, you see, that depends. </em></u></h2><h2><u><em>The firsy thing we have to tak intp account is the angle at witch the sun's rays hit the earth, and that fact can make all the difference, seeing as it does discriminate against seasons. It's more likely that i the winter, a more drastic effect would talk.</em></u></h2><h2 /><h2 /><h2 /><h2>oωo</h2>
F~1/r²
doubling the distance r, Decreases the force by ¼
B Ik it all just know who they’ll you
Answer:
0.20kg-m^2
Explanation:
Let the linear velocity of the rope(=of pulley) is v m/s
Using kinematic equation
=> v = u + at
=>v = 0 + 4.9a
=>v = 4.9a ------------ eq1
By v^2 = u^2 + 2as
=>v^2 = 0 + 2 x v/4.9 x 1.2
=>4.9v^2 - 2.4v = 0
=>v(4.9v - 2.4) = 0
=>v = 2.4/4.9 = 0.49 m/s
Thus by v = r x omega
=>omega = v/r = 0.49/0.02 = 24.49 rad/sec
BY W = F x s = 50 x 1.2 = 60 J
=>KE(rotational) = W = 1/2 x I x omega^2
=>60 = 1/2 x I x (24.49)^2
=>I = 0.20 kg-m^2