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Vladimir [108]
3 years ago
7

A laboratory technician drops a 72.0 g sample of unknown solid material, at a temperature of 80.0°C, into a calorimeter. The cal

orimeter can, initially at 11.0°C, is made of 187 g of copper and contains 203 g of water. The final temperature of the calorimeter can and contents is 39.4°C. What is the specific heat of the unknown sample? Please give your answer in units of J/kg.°C.
Physics
1 answer:
Natalija [7]3 years ago
7 0

Answer : The specific heat of unknown sample is, 8748.78J/kg^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-[q_2+q_3]

m_1\times c_1\times (T_f-T_1)=-[m_2\times c_2\times (T_f-T_2)+m_3\times c_3\times (T_f-T_2)]

where,

c_1 = specific heat of unknown sample = ?

c_2 = specific heat of water = 4186J/kg^oC

c_3 = specific heat of copper = 390J/kg^oC

m_1 = mass of unknown sample = 72.0 g  = 0.072 kg

m_2 = mass of water = 203 g  = 0.203 kg

m_2 = mass of copper = 187 g  = 0.187 kg

T_f = final temperature of calorimeter = 39.4^oC

T_1 = initial temperature of unknown sample = 80.0^oC

T_2 = initial temperature of water and copper = 11.0^oC

Now put all the given values in the above formula, we get

0.072kg\times c_1\times (39.4-80.0)^oC=-[(0.203kg\times 4186J/kg^oC\times (39.4-11.0)^oC)+(0.187kg\times 390J/kg^oC\times (39.4-11.0)^oC)]

c_1=8748.78J/kg^oC

Therefore, the specific heat of unknown sample is, 8748.78J/kg^oC

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Answer:

Potential difference = 245 V

Explanation:

First, we have to find velocity at which ionized molecules are accelerated into a magnetic field. Here, magnetic force acts as a centripetal force due to circular path of molecules towards detector slot.

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Answer:

La resistencia que debe ser conectada en paralelo con una de 20 Ω para hacer una  resistencia combinada de 15 Ω tiene un valor de 60 Ω

Explanation:

Las resistencias son aquellos dispositivos en los circuitos eléctricos que suelen emplearse para oponerse al paso de la corriente eléctrica.

Se denomina resistencia resultante o equivalente al valor de la resistencia que se obtiene al considerar un conjunto de ellas.

Cuando tenes resistencias en paralelo la corriente se divide y circula por varios caminos.

La resistencia equivalente de un circuito de resistencias en paralelo es igual al recíproco de la suma de los inversos de las resistencias individuales:

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se obtiene:

R2=60 Ω

<u><em>La resistencia que debe ser conectada en paralelo con una de 20 Ω para hacer una  resistencia combinada de 15 Ω tiene un valor de 60 Ω</em></u>

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