=(3x^3-y^2)^2 [ open it in (a-b)^2 form]
=(3x^3)^2-2.3x^3.y^2+(y^2)^2
=3^2x^3×2-6x^3y^2+y^2×2
=9x^6-6x^3y^2+y^4. ans
The first digit of a number can be 1-9. The 2nd and the 3rd digit can be 1-10. The last digit can be 0 or 5 ( 2 numbers ):
9 * 10 * 10 * 2 = 1,800
She could pick 1,800 different 4-digit numbers.
Answer:
80
Step-by-step explanation:
Answer:
3x + 472
Step-by-step explanation:
