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3 years ago

Select the correct location on the image.

Chemistry

1 answer:

Mice21 [21]3 years ago

7 0

Answer:

The third one from the left–the graduated cylinder.

Explanation:

The laboratory apparatus that gives an "accurate" or "precise" measurement of a liquid's volume is the graduated cylinder. All you have to do is to pour the liquid into the cylinder and read its measurement using the calibrated scale.

The graduated cylinder comes in different sizes, which means the scale divisions will depend on its size. When reading the measurement, it is important to take note to read at the bottom of the meniscus because it gives the most accurate volume.

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4 years ago

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The average propane cylinder for a residential grill holds approximately 18 kg of propane. how much energy (in kj) is released b

Angelina_Jolie [31]

Let's begin with the basic values that will be used in the solution.

The formula of propane is C3H8. It is an alkane, a hydrocarbon with the general formula of CnH2n+2. Notice that hydrocarbons have only Carbon and Hydrogen atoms. Its molar mass (M) is 44 g.

Molar Mass Calculation is done as like that
C=12 g/mol, H=1 g/mol. 1 mole propane has 3 moles Carbon atoms and 8 mole Hydrogen atoms. M(C3H8)= 3*12+ 8*1= 44 g

Combustion reaction of hydrocarbons gives carbon dioxide and water by releasing energy. That energy is called as enthalpy of combustion (ΔHc°).

ΔHc° of propane equals -2202.0 kj/mol. Burning of 1 mole C3H8 releases 2202 kj energy. Minus sign only indicates that the energy is given out ( an exothermic reaction ).

Let's write the combustion reaction.
C3H8 + O2 ---> CO2 + H20 (unbalanced) ΔHc° = -2202 kj/mol

Now, we calculate mole of 20 kg propane. Convert kilogram into gram since we use molar mass is defined in grams.
mole=mass/molar mass ; n=m/M ; n= 20000 g /44 (g/mol)=454 mole

1 mole propane releases 2202 kj energy.
454 mole propane release 2202 kj *454= 1000909 kj

The answer is 1000909 kj.

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4 years ago

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3 years ago

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The correct option is C.
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A 33.6 mL solution of KCl has a mass of 27.29 g. After evaporating to dryness, the dry salt residues has a mass of 6.31 g. Calcu

bixtya [17]

For the molarity and the percentage of the mass of kcl are mathematically given as

%m/m = 23.1%, molarity = 3.38M

<h3>What is the molarity?</h3>

Generally, the equation for the percentage of the mass of kcl is mathematically given as

(mass of kcl/mass of solution)x 100

therefore

%m/m = (6.31/27.29)x100

%m/m = 23.1%

The molarity

(no of mol/ vol of sol)

molarity = 0.0846mol/0.0250 L

molarity = 3.38M

In conclusion, the molarity is given as

molarity = 3.38M