Answer:
375 grams of 4% NaOH solution contains 15 grams NaOH
Explanation:
Given 4% solution of NaOH = 4g NaOH/100 g Solution
=> 4g NaOH/100g Soln = 15 g NaOH / X
=> X = 15 g NaOH (100 g Soln) / 4 g NaOH = 375 grams Soln contains 15 g NaOH.
Answer:
The most accurate way to determine an object's volume, especially in the case of an irregularly shaped object, is to immerse it in water and measure the amount of water it displaces. A graduated cylinder large enough to hold both the object and enough water to fully immerse it is the best tool for this job.
The number of moles of KF needed to prepare the solution is 3 moles
<h3>What is molarity?</h3>
Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>How to determine the mole of KF </h3>
- Volume = 2500 mL = 2500 / 1000 = 2.5 L
- Molarity = 1.2 M
- Mole of KF =?
Molarity = mole / Volume
1.2 = mole of KF / 2.5
Cross multiply
Mole of KF = 1.2 × 2.5
Mole of KF = 3 moles
Learn more about molarity:
brainly.com/question/9468209
#SPJ1
To overcome the forces of attraction
intermolecular forces of attraction for the liquids and gases
Answer : The correct option is, (7) 332 mL
Explanation : Given,
Density of solution of sulfuric acid = 
38.1 % acid by mass that means 38.1 grams of sulfuric acid present in 100 grams of solution of sulfuric acid.
Now we have to calculate the mass of solution of sulfuric acid.
As, 38.1 grams of sulfuric acid present in 100 grams of solution of sulfuric acid
So, 163 grams of sulfuric acid present in
grams of solution of sulfuric acid
Now we have to calculate the volume of sulfuric acid solution.



Therefore, the volume of sulfuric acid solution needed is 332 mL.