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2 years ago

What’s the value for 2.3 + 4.09 =n

Mathematics

1 answer:

Rashid [163]2 years ago

6 0

Answer:

n = 6.39

Explanation:

2.3 + 4.09 = n
6.39 = n

Swap the sides of the equation
n = 6.39

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8.4 x 5.2 show your work

LuckyWell [14K]

Answer:

43.68

Step-by-step explanation:

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2 years ago

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Given f(x) = 2x + 3 and g(x) = x - 9, what is f(x) + g(x)?

Orlov [11]

Solution:

f(x) = 2x + 3
g(x) = x - 9

f(x) + g(x)
= (2x + 3) + (x - 9)
= 2x + x + 3 - 9
= 3x - 6

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3 years ago

Find the value of x

marishachu [46]

Answer:

x = 5

Step-by-step explanation:

6 - 8x = 6x - 8x - 24

(add the x's on each side)

6 - 8x = -2x - 24

(pass -2x on the other side (adding))

6 - 6x = -24

(pass the 6 to the other side (subtracting))

- 6x = - 30

(divide by -6 on both sides)

x = 5

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2 years ago

What is 0.142857 repeating as a fraction????

algol [13]

1/7 I believe is the right answer

3 0

2 years ago

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given abc with a(-4 -2), b(4,4), and c(18,-8). write the equation of the line that contains the altitude that passes through b i

Tresset [83]

check the picture below.

so red line of BD is perpendicular to AC, hmmmm let's firstly find the slope of AC, bearing in mind that perpendicular lines have <u>negative reciprocal</u> slopes.

$\bf A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad C(\stackrel{x_2}{18}~,~\stackrel{y_2}{-8}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-(-2)}{18-(-4)}\implies \cfrac{-8+2}{18+4} \\\\\\ \cfrac{-6}{22}\implies -\cfrac{3}{11} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{3}{11}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{11}{3}}\qquad \stackrel{negative~reciprocal}{\cfrac{11}{3}}}\impliedby \textit{BD's slope}$

so we're really looking for the equation of a line whose slope is 11/3 and runs through B(4,4). Keeping in mind that

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$\bf B(\stackrel{x_1}{4}~,~\stackrel{y_1}{4})~\hspace{10em} slope = m\implies \cfrac{11}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=\cfrac{11}{3}(x-4)$

$\bf \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}\textit{ to do away with the denominators}}{3(y-4)=3\left( \cfrac{11}{3}(x-4) \right)\implies 3y-12=11(x-4)} \\\\\\ 3y-12=11x-44\implies 3y=11x-32 \\\\\\ -11x+3y=-32\implies \blacktriangleright 11x - 3y= 32\blacktriangleleft$

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2 years ago